在python中将“for循环”转换为“while循环”

Question

我试图通过将for循环替换为while循环来转换代码。
这是我想要转换的代码

下面代码段中代码的函数。由@Sameer提问

    from random import sample
    def shuffle(s): return sample(s,len(s)) 
    rBase = range(base)
    base  = 2
    side  = base*base
    def pattern(r,c):
        return (base*(r%base)+r//base+c)%side

我遇到问题的代码

    rows = []
    cols = []
    data = []
    for r in shuffle(rBase):
        for g in shuffle(rBase):
            rows.append(g*base+r)
    for c in shuffle(rBase):
        for g in shuffle(rBase):
            cols.append(g*base+c)
    nums = shuffle(range(1,side+1))
    for r in rows:
        for c in cols:
            data.append(nums[pattern(r,c)])

这是我的代码

rows = []
cols = []
data = []
s = shuffle(rBase)
i,j = 0,0
while i < len(s):
    r = s[i]
    while j < len(s):
        s2 = shuffle(rBase)
        g = s2[i]
        rows.append(g*base+r)
        j+=1
    i += 1
i,j = 0,0
s = shuffle(rBase)
while i < len(s):
    c = s[i]
    while j < len(s):
        s2 = shuffle(rBase)
        g = s2[i]
        cols.append(g*base+c)
        j += 1
    i += 1
nums = shuffle(range(1,side+1))
i,j =0,0
while i < len(rows):
    r = rows[i]
    while j < len(cols):
        c = cols[i]
        data.append(nums[pattern(r,c)])
        j += 1
    i += 1

由于隐私原因，部分代码被省略。
预期输出，for循环代码段的ie输出是一个长度为（基数**4）的列表，包含从1到基数**2的每个数字，正好是基数**2次。 例如： 如果基数为2： 预期的输出类似于[3, 2, 1, 4, 4, 1, 3, 2, 1, 4, 2, 3, 2, 3, 4, 1]

实际输出是一个长度基的列表，每个元素是一个介于1和基**2之间的随机数。（包括基**2） 例如： 如果基数为2： 实际输出类似于[1,1]或[2,2]或[3,3]或[4,4]

Answer 1

变量j=0应在内部while循环之前定义。目前，您的内部while仅运行'len（s）'次，而且您在第二个循环中使用'i'进行索引，您应该在那里使用j

这应该行得通

from random import sample

def shuffle(s): return sample(s,len(s)) 
base  = 2
rBase = range(base)
side  = base*base
def pattern(r,c):
    return (base*(r%base)+r//base+c)%side

rows = []
cols = []
data = []
for r in shuffle(rBase):
    for g in shuffle(rBase):
        rows.append(g*base+r)
for c in shuffle(rBase):
    for g in shuffle(rBase):
        cols.append(g*base+c)
print(rows)
print(cols)        
nums = shuffle(range(1,side+1))
for r in rows:
    for c in cols:
        data.append(nums[pattern(r,c)])

print(data)

rows = []
cols = []
data = []
s = shuffle(rBase)
s2 = shuffle(rBase)
i = 0
while i < len(s):
    r = s[i]
    j = 0
    while j < len(s):
        g = s2[j]
        j = j + 1
        rows.append(g*base+r)
    i = i + 1
i = 0
s = shuffle(rBase)
s2 = shuffle(rBase)
while i < len(s):
    c = s[i]
    j = 0
    while j < len(s):
        g = s2[j]
        cols.append(g*base+c)
        j += 1
    i += 1
nums = shuffle(range(1,side+1))    
i =0
while i < len(rows):
    r = rows[i]
    j = 0
    while j < len(cols):
        c = cols[j]
        data.append(nums[pattern(r,c)])
        j += 1
    i += 1
print(rows)
print(cols)
print(data)