擅长:python、mysql、java
<p>这行吗</p>
<pre><code>df2['range'] = df2.apply(lambda row: list(range(row['start'],row['start']-11,-1)),axis=1)
df2
</code></pre>
<p>输出</p>
<pre><code>
ID loc start range
0 A Lon 20 [20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10]
1 B Tok 10 [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
2 C Ber 30 [30, 29, 28, 27, 26, 25, 24, 23, 22, 21, 20]
3 D Ams 40 [40, 39, 38, 37, 36, 35, 34, 33, 32, 31, 30]
4 E Rom 43 [43, 42, 41, 40, 39, 38, 37, 36, 35, 34, 33]
</code></pre>
<p>或者,如果需要逗号分隔:</p>
<pre><code>df2['range'] = df2.apply(lambda row: ','.join([str(v) for v in range(row['start'],row['start']-11,-1)]),axis=1)
</code></pre>
<p>得到</p>
<pre><code> ID loc start range
0 A Lon 20 20,19,18,17,16,15,14,13,12,11,10
1 B Tok 10 10,9,8,7,6,5,4,3,2,1,0
2 C Ber 30 30,29,28,27,26,25,24,23,22,21,20
3 D Ams 40 40,39,38,37,36,35,34,33,32,31,30
4 E Rom 43 43,42,41,40,39,38,37,36,35,34,33
</code></pre>