在python中访问正则表达式捕获组

Question

ptx捕获了我想要的大部分内容。因为我不能将许多东西组合到一个正则表达式中），所以我创建了第二个ptx1正则表达式，它还应该捕获以下字符序列： One Department，One foreign Department，Two office

    text_list = [' something\npatternx: text_i_want One Department',' something patternx: text_i_want One foreign Department',' something\n patternx: text_i_want Two office']
    text_list = ' '.join(map(str, text_list))
    ptx = re.compile(r'(\s+something(?:\s+|\\n)*patternx:)(.*)(One\s+foreign)', flags = re.DOTALL)
    ten = ptx.search(text_list)
    try:
        if ten:
            ten = ten.group(2)
        else:
            ten = None
    except:
        pass

我的问题是：为了返回(.*)或text_i_want内容，我需要做什么？我有一种直觉，我需要像访问列表一样访问eleven，因为它有太多的捕获组eleven[0].group(1)，以便从列表中获取第一个元素并获取第二个组。但这也不起作用

你可以这样想text_list

text_list = ['...something\npatternx: text_i_want One Department',
'...something patternx: text_i_want One foreign Department',
'...something\n patternx: text_i_want Two office']

更新

    text_list = [' something\npatternx: text_i_want One Department',' something patternx: text_i_want One foreign Department',' something\n patternx: text_i_want Two office']
    text_list = ' '.join(map(str, text_list))
    ptx = re.compile(r'\bsomething\s+patternx:(.*?)\b(?:One\s+(?:Department|foreign(?:\s+Department)?)|Two\s+office)\b', flags = re.DOTALL)
    ten = ptx.search(text_list)
    try:
        if ten:
            ten = ten.group(2)
        else:
            ten = None
    except:
        pass

Answer 1

当考虑到右边的备选方案时，看起来好像你被欺骗了

你需要使用

\bsomething\s+patternx:(.*?)\b(?:One\s+foreign|One\s+Department|One\s+foreign\s+Department|Two\s+office)\b

可以简称为

\bsomething\s+patternx:(.*?)\b(?:One\s+(?:Department|foreign(?:\s+Department)?)|Two\s+office)\b

见regex demo详细信息：

• \bsomething\s+patternx:-整个单词something，一个或多个空格，patternx:字符串
• (.*?)-第1组：任何零个或多个字符，尽可能少
• \b(?:One\s+(?:Department|foreign(?:\s+Department)?)|Two\s+office)\b-作为整个单词的{}、{}、{}或{}

见Python demo：

import re
text_list = [' something\npatternx: text_i_want One Department',' something patternx: text_i_want One foreign Department',' something\n patternx: text_i_want Two office']
text_list = ' '.join(map(str, text_list))
rx = r'\bsomething\s+patternx:(.*?)\b(?:One\s+(?:Department|foreign(?:\s+Department)?)|Two\s+office)\b'
print(re.findall(rx, text_list, re.DOTALL))
# => [' text_i_want ', ' text_i_want ', ' text_i_want ']