高局还是低局

Question

我正在尝试构建一个简单的python游戏，您必须猜测下一个数字是高还是低。计算机可以选择的数字范围是1，21

用户输入高或低（H或L），计算机随机生成第二个数字，然后对照第一个数字进行检查，以确定用户猜测是否正确

我要面对的问题是，一旦计算机生成了第二个数字，我希望循环继续以该数字作为用户必须猜测的数字

例如：

电脑号码-11 用户输入更高 第二个号码-15

用户是正确的。然后他们必须猜测下一个数字是高于还是低于15

我无法让第二个数字成为用户猜测的数字，相反，循环再次开始，数字始终为11，这是我设置的起点

有人知道如何让它工作吗

代码：

streak = 0
print(artwork.title)
print("Welcome to High or Low!\nDo you think the next number will be higher or lower?")
print("\nThe game always starts with the number 11, get a streak of 5 to win!")
end_of_game = False


while not end_of_game:
first_number = 11
second_number = random.randint(1, 21)

player_input = input("\nHigher or Lower? Type H or L\n").lower()

if player_input == "h" and second_number > first_number:
    streak += 1
    print(f"{second_number} Correct!")
    first_number = second_number
    print(f"Current Streak is: {streak}")
    print(f"\n\nThe current number is: {first_number}")
    if streak == 5:
        print("Congratulations YOU WIN!")
        end_of_game = True
elif player_input == "l" and second_number > first_number:
    print(f"{second_number}, Unlucky")
    print("\nTry again, the number is 11")
    streak = 0
elif player_input == "h" and second_number < first_number:
    print(f"{second_number}, Unlucky")
    print("\nTry again, the number is 11")
    streak = 0
elif player_input == "l" and second_number < first_number:
    streak += 1
    print(f"{second_number} Correct!")
    first_number = second_number
    print(f"Current Streak is: {streak}")
    print(f"\n\nThe current number is: {first_number}")
    if streak == 5:
        print("Congratulations YOU WIN!")
        end_of_game = True

我只做了一个星期，所以我的代码看起来像字母汤。。抱歉

Answer 1

问题是您正在将循环顶部的first_number重置为11：

while not end_of_game:
    first_number = 11
    ...

因此，即使在玩家获胜时在循环中设置了first_number = second_number，它也只是在下一次迭代中重置为11

要解决此问题，只需将初始化移出循环，使其在进入循环之前只执行一次：

first_number = 11
while not end_of_game:
    ...