列表中的相同位置？

Question

words = ['me','me']
def nth_char(words):
    newArray = []
    for i in words:
        x = words.index(i)
        newArray.append(x)
    return newArray

我得到的不是[0,1]，而是[0,0]，为什么？？？ 还有其他更简单的方法吗？ 我是编程新手，欢迎任何帮助

Answer 1

始终.index()返回找到的第一个索引，您需要签入循环并使用enumerate如下所示：

>>> words = ['me', 'you','me']
>>> for idx, w in enumerate(words):
...    if w == 'me':
...        print(idx)
0
2

>>> [idx for idx, w in enumerate(words) if w == 'me']
[0,2]

# for more explanation
>>> for idx, w in enumerate(words):
...    print(idx, w)
0 me
1 you
2 me

Answer 2

试试这个：

words = ['me','me']
def nth_char(words):
    newArray = []
    for index, element in enumerate(words):
        newArray.append(index)
    return newArray