擅长:python、mysql、java
<p>下面是在<code>lambda</code>中组合<code>set</code>和<code>list</code>的尝试:</p>
<pre><code>df_ex[8] = [x for x in df_ex[[0,1,2,3,4,5,6,7]].values.tolist()]
df_ex[8] = df_ex[8].apply(lambda x: list(set([y for y in x if str(y)!='nan'])))
</code></pre>
<p>输出:</p>
<pre><code>0 [Morocco, France]
1 [Morocco, France]
2 [Morocco, France]
3 [United States, China]
4 [China]
</code></pre>