使用soaplib xml字符或与号分隔符的Django WebService？

Question

这是我的第一个问题，所以我会尽力做到最好。在

我试图用python2.6和django1.4和soaplib2.0实现一个WebService服务器。在

web服务正在工作，Django在Django开发服务器中正常地提供服务。在

以下是Django视图和url的代码：

视图.py

from soaplib.core.service import rpc, DefinitionBase, soap
from soaplib.core.model.primitive import String, Integer, Boolean
from soaplib.core.model.clazz import Array
from soaplib.core import Application
from soaplib.core.server.wsgi import Application as WSGIApplication
from django.http import HttpResponse

class HelloWorldService(DefinitionBase):
    @soap(String,Integer,_returns=Array(String))
    def say_smello(self,name,times):
        results = []
        for i in range(0,times):
            results.append('Hello, %s'%name)
        return results
    @soap(String,_returns=Boolean)
    def xml(self,xml):
        result = xml
        return True
    @soap(String,_returns=String)
    def xml2(self,xml2):
        return xml2



class DjangoSoapApp(WSGIApplication):
    csrf_exempt = True

    def __init__(self, services, tns):
        """Create Django view for given SOAP soaplib services and
tns"""

        return super(DjangoSoapApp,
            self).__init__(Application(services, tns))

    def __call__(self, request):
        django_response = HttpResponse()

        def start_response(status, headers):
            django_response.status_code = int(status.split(' ', 1)[0])
            for header, value in headers:
                django_response[header] = value

        response = super(DjangoSoapApp, self).__call__(request.META,
            start_response)
        django_response.content = '\n'.join(response)

        return django_response

my_soap_service = DjangoSoapApp([HelloWorldService], __name__)

网址.py

^{pr2}$

问题是，我想把一个xml和xml中的信息传递给WebService方法xml或xml2。我有错误。在

如果我传递一个不带“&；”等字符的简单字符串，则一切正常，例如：

首先，我们导入sud并将suds设置为Debug：

from suds.client import Client
import logging
logging.basicConfig(level=logging.INFO)
logging.getLogger('suds.client').setLevel(logging.DEBUG)

现在让我们开始打电话给de WS：

WSDL = "http://server.test/soap/wsdl"
client = Client(WSDL)
client.service.xml('x and y')

工作完美，我得到了“真实”的结果，肥皂水的记录显示我正在这样做：

DEBUG:suds.client:sending to (http://server.test/soap/wsdl)
message:
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:ns0="soap.views" xmlns:ns1="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
   <SOAP-ENV:Header/>
   <ns1:Body>
      <ns0:xml>
         <ns0:xml>x and y</ns0:xml>
      </ns0:xml>
   </ns1:Body>
</SOAP-ENV:Envelope>
DEBUG:suds.client:headers = {'SOAPAction': '"xml"', 'Content-Type': 'text/xml; charset=utf-8'}
DEBUG:suds.client:http succeeded:
<?xml version='1.0' encoding='utf-8'?>
<senv:Envelope xmlns:wsa="http://schemas.xmlsoap.org/ws/2003/03/addressing" xmlns:plink="http://schemas.xmlsoap.org/ws/2003/05/partner-link/" xmlns:xop="http://www.w3.org/2004/08/xop/include" xmlns:senc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:s0="soap.views" xmlns:s12env="http://www.w3.org/2003/05/soap-envelope/" xmlns:s12enc="http://www.w3.org/2003/05/soap-encoding/" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:senv="http://schemas.xmlsoap.org/soap/envelope/"  xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/"><senv:Body><s0:xmlResponse><s0:xml    Result>true</s0:xmlResult></s0:xmlResponse></senv:Body></senv:Envelope>
True

但如果我这么做了：

client.service.xml('x &  y')

不工作，它以一个suds超时结束，服务器报告管道破裂，这是suds日志告诉我的：

DEBUG:suds.client:sending to (http://server.test/soap/wsdl)
message:
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:ns0="soap.views" xmlns:ns1="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
   <SOAP-ENV:Header/>
   <ns1:Body>
      <ns0:xml>
         <ns0:xml>x &amp;  y</ns0:xml>
      </ns0:xml>
   </ns1:Body>
</SOAP-ENV:Envelope>
DEBUG:suds.client:headers = {'SOAPAction': '"xml"', 'Content-Type': 'text/xml; charset=utf-8'}

这是关于肥皂水的错误：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/site-packages/suds/client.py", line 542, in __call__
    return client.invoke(args, kwargs)
  File "/usr/lib/python2.6/site-packages/suds/client.py", line 602, in invoke
    result = self.send(soapenv)
  File "/usr/lib/python2.6/site-packages/suds/client.py", line 643, in send
    reply = transport.send(request)
  File "/usr/lib/python2.6/site-packages/suds/transport/https.py", line 64, in send
    return  HttpTransport.send(self, request)
  File "/usr/lib/python2.6/site-packages/suds/transport/http.py", line 77, in send
    fp = self.u2open(u2request)
  File "/usr/lib/python2.6/site-packages/suds/transport/http.py", line 118, in u2open
    return url.open(u2request, timeout=tm)
  File "/usr/lib/python2.6/urllib2.py", line 391, in open
    response = self._open(req, data)
  File "/usr/lib/python2.6/urllib2.py", line 409, in _open
    '_open', req)
  File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.6/urllib2.py", line 1190, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.6/urllib2.py", line 1165, in do_open
    raise URLError(err)
urllib2.URLError: <urlopen error timed out>

感谢这个链接：http://grokbase.com/p/python/soap/125nhj9bdm/python-suds-xml-encoding-issue我发现是的，如果我发布类似于以下内容的web服务：

client.service.xml("x & y")

我说得对：

DEBUG:suds.client:sending to (http://server.test/soap/wsdl)
message:
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:ns0="soap.views" xmlns:ns1="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
   <SOAP-ENV:Header/>
   <ns1:Body>
      <ns0:xml>
         <ns0:xml>x &amp;amp; y</ns0:xml>
      </ns0:xml>
   </ns1:Body>
</SOAP-ENV:Envelope>
DEBUG:suds.client:headers = {'SOAPAction': '"xml"', 'Content-Type': 'text/xml; charset=utf-8'}
True

如果我使用xml2方法，那么我可以看到返回WebService的内容是：

client.service.xml2("x & y")

以及肥皂水日志：

DEBUG:suds.client:sending to (http://server.test/soap/wsdl)
message:
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:ns0="soap.views" xmlns:ns1="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
   <SOAP-ENV:Header/>
   <ns1:Body>
      <ns0:xml2>
         <ns0:xml2>x &amp;amp; y</ns0:xml2>
      </ns0:xml2>
   </ns1:Body>
</SOAP-ENV:Envelope>
DEBUG:suds.client:headers = {'SOAPAction': '"xml2"', 'Content-Type': 'text/xml; charset=utf-8'}


DEBUG:suds.client:http succeeded:
<?xml version='1.0' encoding='utf-8'?>
<senv:Envelope xmlns:wsa="http://schemas.xmlsoap.org/ws/2003/03/addressing" xmlns:plink="http://schemas.xmlsoap.org/ws/2003/05/partner-link/" xmlns:xop="http://www.w3.org/2004/08/xop/include" xmlns:senc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:s0="soap.views" xmlns:s12env="http://www.w3.org/2003/05/soap-envelope/" xmlns:s12enc="http://www.w3.org/2003/05/soap-encoding/" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:senv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/"><senv:Body><s0:xml2Response><s0:xml2Result>x &amp; y</s0:xml2Result></s0:xml2Response></senv:Body></senv:Envelope>
x & y

但我不认为问题出在SUDS中，因为我使用这个版本的SUDS将XML推送到javawebservices，但是我还没有找到soaplib的方法。在

有什么想法吗？这让我有点疯狂

我的最终目标是使用Soaplib实现Webservice，并从Java的soap客户机向其推送XML。在

谢谢

Answer 1

也许你可以把它包装成一个cdata标签，而不是转义。更多信息请访问http://en.wikipedia.org/wiki/CDATA

<![CDATA[
x & y
]]>

Answer 2

好的，解决了：D

我只能更改服务器端，所以我将代码迁移到spyne，工作起来很有魅力。在

https://github.com/arskom/spyne

我在他们的网上找到了这个：

 Soaplib-2.0 was never released as a stable package, but the branch is still available

从soaplib到Rpclib再从那里到Spyne。在

我确实发现了一个新的bug，这次是在suds上，但是我只是用来测试的suds，但是如果我使用其他客户机，SoapUI或Java客户机，就完美地工作了。在

用PIP安装后，这是Django代码：

网址.py

^{pr2}$

视图.py

from django.views.decorators.csrf import csrf_exempt
from spyne.server.django import DjangoApplication
from spyne.model.primitive import String
from spyne.service import ServiceBase
from spyne.interface.wsdl import Wsdl11
from spyne.protocol.soap import Soap11
from spyne.application import Application
from spyne.decorator import srpc



class ServiceWsTest(ServiceBase):
    @srpc(String, _returns=String)
    def testMethod(string):
        return string

ws_test = csrf_exempt(DjangoApplication(Application([ServiceWsTest],
    'http://example.com',
    in_protocol=Soap11(),
    out_protocol=Soap11(),
    interface=Wsdl11(),
)))

从现在起，我将继续与这个图书馆合作