如何在Python中使用正则表达式删除结束方括号？

Question

我有一个凌乱的字符串列表（list_strings），在这里我可以使用regex删除不需要的字符，但我也很难删除结束括号]。我怎样才能删除这些？我想我很接近

#the list to clean
list_strings = ['[ABC1: text1]', '[[DC: this is a text]]', '[ABC-O: potatoes]', '[[C-DF: hello]]']

#remove from [ up to : 
for string in list_strings:
  cleaned = re.sub(r'[\[A-Z\d\-]+:\s*', '', string)
  print(cleaned)

# current output

>>>text1]
>>>this is a text]]
>>>potatoes]
>>>hello]

所需输出：

text1
this is a text
potatoes
hello

Answer 1

我将使用rstrip()和split()功能使用不同的方法处理正则表达式：

list_strings = ['[ABC1: text1]', '[[DC: this is a text]]', '[ABC-O: potatoes]', '[[C-DF: hello]]']

cleaned = [s.split(': ')[1].rstrip(']') for s in list_strings]
print(cleaned) # ['text1', 'this is a text', 'potatoes', 'hello']

Answer 2

我会在这里使用列表：

list_strings = ['[ABC1: text1]', '[[DC: this is a text]]', '[ABC-O: potatoes]', '[[C-DF: hello]]']
cleaned = [x.split(':')[1].strip().replace(']', '') for x in list_strings]
print(cleaned)  # ['text1', 'this is a text', 'potatoes', 'hello']

Answer 3

用这种方式编写代码。在这里修复OP的尝试本身。您的正则表达式正在做所有的事情，唯一的一点就是添加一个OR条件，在这里我们可以提到替换1次或多次出现的]

import re
list_strings = ['[ABC1: text1]', '[[DC: this is a text]]', '[ABC-O: potatoes]', '[[C-DF: hello]]']
for string in list_strings:
  cleaned = re.sub(r'[\[A-Z\d\-]+:\s+|\]+$', '', string)
  print(cleaned)