擅长:python、mysql、java
<p>你可以用<code>str.contains</code></p>
<pre><code>df['exist1'] = df['Location'].str.contains('|'.join(df['Job Title'].dropna().tolist()))
</code></pre>
<p>如果您想为每一行匹配</p>
<pre><code>df1=df.dropna()
df1['exist1'] = [ x in y for x, y in zip(df1['Location'], df1['Job Title'])]
df['exist1']=df1['exist1']
</code></pre>