<p><strong>解决方案:</strong><br/>
这应该可以解决您的目的:)</p>
<pre><code>D = [{1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1:
10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2:
10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3:
10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}, {1: 10, 2: 10, 3: 10}]
C = [[1, 2, 1], [1, 2, 1], [2, 1, 1], [3, 1, 1], [1, 1, 2], [1, 1, 2], [1, 2, 2], [1, 1, 1], [1, 2,
2], [1, 1, 3], [2, 1, 2], [2, 1, 2], [2, 2, 1], [2, 2, 1], [2, 1, 1], [1, 3, 1]]
for d, c in zip(D, C):
for key, val in d.items():
d[key] = val + c.pop()
print(D)
</code></pre>
<p><strong>输出:</strong></p>
<pre><code>[{1: 11, 2: 12, 3: 11}, {1: 11, 2: 12, 3: 11}, {1: 11, 2: 11, 3: 12}, {1: 11, 2: 11, 3: 13}, {1: 12, 2: 11, 3: 11}, {1: 12, 2: 11, 3: 11}, {1: 12, 2: 12, 3: 11}, {1: 11, 2: 11, 3: 11}, {1: 12, 2: 12, 3: 11}, {1: 13, 2: 11, 3: 11}, {1: 12, 2: 11, 3: 12}, {1: 12, 2: 11, 3: 12}, {1: 11, 2: 12, 3: 12}, {1: 11, 2: 12, 3: 12}, {1: 11, 2: 11, 3: 12}, {1: 11, 2: 13, 3: 11}]
</code></pre>