2024-06-16 12:17:18 发布
网友
我需要帮助做一个for循环来创建一个散点图,显示由一个系统分组的两个变量。 我的df是:
WTG Power WSPD A0201 2000 12.1 A0202 1800 9.7 A0201 1000 6.6 A0202 1150 7.8 A0203 760 5.8 A0203 1353 8.8
所以我需要的是每个涡轮机的散点图,x轴是WSPD,y轴是功率
谢谢
Plotly express非常适合这一点。不需要For Loop
For Loop
fig = px.scatter(df, x='WSPD', y = 'Power', color = 'WTG')
但是如果出于某种原因For Loop更适合您,您可以使用plotly.graph_objects:
fig = go.Figure() colors = px.colors.qualitative.Plotly for i, cat in enumerate(df['WTG'].unique()): dfp = df[df['WTG']==cat] fig.add_trace(go.Scatter(x=dfp['WSPD'], y = dfp['Power'], mode = 'markers', marker_color = colors[i])) fig.show()
import plotly.graph_objects as go import plotly.express as px import pandas as pd df = pd.DataFrame({'WTG': {0: 'A0201', 1: 'A0202', 2: 'A0201', 3: 'A0202', 4: 'A0203', 5: 'A0203'}, 'Power': {0: 2000, 1: 1800, 2: 1000, 3: 1150, 4: 760, 5: 1353}, 'WSPD': {0: 12.1, 1: 9.7, 2: 6.6, 3: 7.8, 4: 5.8, 5: 8.8}}) fig = px.scatter(df, x='WSPD', y = 'Power', color = 'WTG') fig.show()
import plotly.graph_objects as go import plotly.express as px import pandas as pd df = pd.DataFrame({'WTG': {0: 'A0201', 1: 'A0202', 2: 'A0201', 3: 'A0202', 4: 'A0203', 5: 'A0203'}, 'Power': {0: 2000, 1: 1800, 2: 1000, 3: 1150, 4: 760, 5: 1353}, 'WSPD': {0: 12.1, 1: 9.7, 2: 6.6, 3: 7.8, 4: 5.8, 5: 8.8}}) fig = go.Figure() colors = px.colors.qualitative.Plotly for i, cat in enumerate(df['WTG'].unique()): dfp = df[df['WTG']==cat] fig.add_trace(go.Scatter(x=dfp['Power'], y = dfp['WSPD'], mode = 'markers', marker_color = colors[i], name = cat)) fig.show()
Plotly express非常适合这一点。不需要
For Loop
但是如果出于某种原因
For Loop
更适合您,您可以使用plotly.graph_objects:完整代码,plotly express:
完整代码,绘图对象:
相关问题 更多 >
编程相关推荐