从10开始的数字反转模式。(模式问题)

2024-06-02 07:01:20 发布

您现在位置:Python中文网/ 问答频道 /正文

这是我要打印的图案

1
3.2
654
10987

现在我有了一个解决方案,但我不知道它到底是如何工作的

解决方案:

length = 6
start = 1
stop = 2
currentNumber = stop
for row in range(stop, length):
    for col in range(start, stop):
        currentNumber -= 1
        print(currentNumber, end=" ")
    print(" ")
    start = stop
    stop += row
    currentNumber = stop

我认为它是这样工作的:

# for row in range(2, 6): 2, 3, 4, 5,
# for col in range(1, 2):
#  currentnum = 2-1 = 1
#  print( 1 )
#  start = stop (start = 2)
#  stop += 2 (row = 2,3,4,5) so now stop = 2 + 2 = 4
# currentNumber = 4

# for row in range(4, 6): 4,5
# for col in range(2, 4): 2, 3 means 2 time will loop run
#  currentnum = 4-1 = 3,
#  currentnum = 3-2 = 2
#  print( 3, 2 )
#  start = stop (start = 4)
#  stop += 3 (stro = 4+3 = 7)
#  currentnum = 7

                    **PROBLEM** 

# for row in range(7, 6):    
# for col in range(4, 7): 5,6,7 means 3 time will loop run
#  currentnum = 7-1 = 6,
#  currentnum = 7-2 = 5,
#  currentnum = 7-3 = 4,
#  print( 6, 5, 4)
#  start = stop (start = 7)
#  stop += 3 (stro = 7+3 = 11)
#  currentnum = 11

下面是问题(talking from the #commented calculations):

for i in range(11, 6):
    for j in range(4, 7):
        print("h")
    print("k")
print("j")

由于(11,6),该For循环将不会执行

这就是我的计算出错的地方,我知道我不知道这个解决方案是如何工作的。 任何对当前解决方案有更好的解决方案或解释的人都将不胜感激

只想知道代码是如何工作的

谢谢


Tags: infortimerangecol解决方案startlength
1条回答
网友
1楼 · 发布于 2024-06-02 07:01:20

我认为您理解的问题是每次更改停止时都要重新编写第一个for循环。但是,不应该这样做,因为for循环只在开始时计算,所以在循环已经运行时更改变量stop不应该对循环产生影响,如果这样做是有意义的话。我在这里更正了您的“理解”部分:

#### for loop does not change
# for row in range(2, 6): 2, 3, 4, 5,

### for loop 2 ###
#     for col in range(1, 2):
#         currentNumber -= 1  # 2-1 = 1
#         print(1)
#      start = stop  # (start = 2)
#      stop += 2  # (row currently = 2) so now stop = 2 + 2 = 4
#      currentNumber = 4

### for loop 3 ###
#     for col in range(2, 4): 2, 3 means 2 time will loop run
#         currentnum = 4-1 = 3,
#         currentnum = 3-2 = 2
#         print(3, 2)
#     start = stop  # (start = 4)
#     stop += 3  # (row currently = 3) so now stop = 4 + 3 = 7
#     currentnum = 7

### for loop 4 ###
#     for col in range(4, 7):  # 4, 5, 6 i.e. loop 3 times
#         currentnum = 7-1 = 6,
#         currentnum = 6-1 = 5
#         currentnum = 5 - 1 = 4
#         print(6, 5, 4)
#     start = stop  # (start = 7)
#     stop += 4  # (row currently = 4) so now stop = 7 + 4 = 11
#     currentnum = 11

### for loop 5 ###
#     for col in range(7, 11):  # 7, 8, 9, 10 i.e. loop 4 times
#         currentnum = 11 - 1 = 10
#         currentnum = 10 - 1 = 9
#         currentnum = 9 - 1 = 8
#         currentnum = 8 - 1 = 7
#         print(10, 9, 8, 7)
#     start = stop  # (start = 11)
#     stop += 5  # (row currently = 5) so now stop = 11 + 5 = 16
#     currentnum = 16

希望这是有道理的,但请随时要求澄清。请注意,最后几行并不重要,因为它是最后一个for循环

相关问题 更多 >