在Python中重命名同名文件时，将目录中的所有文件复制到新目录中

Question

我试图将源目录中的每个csv文件及其子文件夹复制到一个新的“mega”文件夹中。最终结果将是一个文件夹，其中除了源目录中的csv文件外，什么也不包含

我面临的问题是，一些csv文件名是相同的。因此，在复制文件时，同名文件将被覆盖。我希望能够重命名它们，而不是覆盖它们。我想重命名文件的格式示例如下：

• abcd
• abcd_1
• abcd_2等

我找到了this thread，但答案对我不起作用

我的代码如下（基于提供的链接）：

movdir = r"Source Directory"
basedir = r"Destination Folder"
# Walk through all files in the directory that contains the files to copy
for root, dirs, files in os.walk(movdir):
    for filename in files:
        # I use absolute path, case you want to move several dirs.
        old_name = os.path.join(os.path.abspath(root), filename)

        # Separate base from extension
        base, extension = os.path.splitext(filename)

        # Initial new name
        new_name = os.path.join(basedir, base, filename)

        # If folder basedir/base does not exist... You don't want to create it?
        if not os.path.exists(os.path.join(basedir, base)):
            print(os.path.join(basedir,base), "not found") 
            continue    # Next filename
        elif not os.path.exists(new_name):  # folder exists, file does not
            shutil.copy(old_name, new_name)
        else:  # folder exists, file exists as well
            ii = 1
            while True:
                new_name = os.path.join(basedir,base, base + "_" + str(ii) + extension)
                if not os.path.exists(new_name):
                   shutil.copy(old_name, new_name)
                   print("Copied", old_name, "as", new_name)
                   break 
                ii += 1

当我运行这段代码时，它只打印出源目录中的每个csv文件都是“未找到”的，并且没有任何文件被复制

如果您能提供任何帮助或信息，我们将不胜感激

Answer 1

尝试以下修改：

movedir = r"source"
basedir = r"destination"
# Walk through all files in the directory that contains the files to copy
for root, dirs, files in os.walk(movdir):
    for filename in files:
        # I use absolute path, case you want to move several dirs.
        old_name = os.path.join(os.path.abspath(root), filename)

        file_path,file_bare_name = os.path.split(filename) # this is were ur code didn't work as u use base as the bare file name and the relative path to source ambiguously.
        base, extension = os.path.splitext(file_bare_name)
        file_relative_path_to_source = root[len(movedir)+1:] #removing the old dir name from the relative path 
        
        if extension=='.csv': # taking only csv files
            # Initial new name
            new_name = os.path.join(basedir, file_bare_name)
            if not os.path.exists(new_name):  # file dosn't exist
                shutil.copy(old_name, new_name)
            else:  # copies being renamed
                ii = 1
                while True:
                    new_name = os.path.join(basedir, file_bare_name + "_" + str(ii) + extension)
                    if not os.path.exists(new_name):
                        shutil.copy(old_name, new_name)
                        print("Copied", old_name, "as", new_name)
                        break 
                    ii += 1