在2D数组Python中编辑元素的简单方法：

Question

我希望能够在2D数组中的特定元素上执行操作，如果它符合标准的话。在下面的示例中，代码生成任何值<；0.5 = 0.

有人知道这样做的简单方法吗？下面是我的代码，但我相信有一个更简单的方法

import numpy as np

x = 5
y = 5

x3 = np.random.rand(x,y)

def choice(arr):
    row = -1
    column = -1
    for i in arr:
        row += 1
        for j in i:
            column += 1
            if j >= 0.5:
                arr[row,column] = j
            else:
                arr[row,column] = 0
                
            if column == y - 1:
                column = -1
    
    return arr

y3 = choice(x3.copy())

Answer 1

将所有<；0.5

>>> x3 = np.random.rand(5, 5)
>>> x3
array([[0.50866152, 0.56821455, 0.88531855, 0.36596337, 0.08705278],
       [0.96215686, 0.19553668, 0.15948972, 0.20486815, 0.74759719],
       [0.36269356, 0.54718917, 0.66196524, 0.82380099, 0.77739482],
       [0.0431448 , 0.47664036, 0.80188153, 0.8099637 , 0.65258638],
       [0.84862179, 0.22976325, 0.03508076, 0.72360136, 0.76835819]])
>>> x3[x3 < .5] = 0
>>> x3
array([[0.50866152, 0.56821455, 0.88531855, 0.        , 0.        ],
       [0.96215686, 0.        , 0.        , 0.        , 0.74759719],
       [0.        , 0.54718917, 0.66196524, 0.82380099, 0.77739482],
       [0.        , 0.        , 0.80188153, 0.8099637 , 0.65258638],
       [0.84862179, 0.        , 0.        , 0.72360136, 0.76835819]])

Answer 2

仅针对枚举和三元条件介绍，您可以执行以下操作：

import numpy as np

x = 5
y = 5

x3 = np.random.rand(x,y)

def choice(arr):
    for row_idx, row in enumerate(arr):
        for col_idx, val in enumerate(row) :
            arr[row_idx,col_idx] = val if val >= 0.5 else 0
    return arr

y3 = choice(x3.copy())

但AKX解决方案更好