使用Javascript向Python REST API发送URL参数

2024-04-28 07:05:50 发布

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我正在尝试使用Javascript将URL参数发送到我在Python上编写的API。 我的Javascript代码如下所示:

function createGetRequest() {
        var request = new XMLHttpRequest();
        request.open('GET', 'some-link/api/', true);
        request.onload = function() {
            var data = JSON.parse(this.response);
            document.getElementById("idk").innerHTML = data.news.entry_news_item_title + "</br>" + data.news.entry_news_item_snippet + "</br>"
            + data.news.entry_news_item_url;
        }
        request.send();
    }

我的Python REST API代码如下:

def index():
NewsFeed = feedparser.parse("https://trends.google.com.tr/trends/trendingsearches/daily/rss?geo=TR")

entry = NewsFeed.entries[0]

return {"news" : {"Status" : "OK",
                              "item" : entry['title'],
                              "entry_news_item_title" : entry['ht_news_item_title'],
                              "entry_news_item_snippet" : entry['ht_news_item_snippet'],
                              "entry_news_item_url" : entry['ht_news_item_url']}}

我希望能够从用户那里获得条目的索引,然后返回相应的条目。换句话说,我希望entry = NewsFeed.entries[0]部分接受变量而不是0。我在网上什么都试过了,但似乎还没弄明白


Tags: 代码apiurldatatitlerequestvarfunction
1条回答
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1楼 · 发布于 2024-04-28 07:05:50

在JavaScript代码中添加条目以获取请求,如下所示:

function createGetRequest() {
    // code to get number/id you are clicking on
    entry_id = getEntryId();
    var request = new XMLHttpRequest();
    //After question marks you can input your GET request parameters
    request.open('GET', `some-link/api/?entry=${entry_id}`, true); //I am using backticks as interpolation  
    request.onload = function() {
        var data = JSON.parse(this.response);
        document.getElementById("idk").innerHTML = data.news.entry_news_item_title + "</br>" + data.news.entry_news_item_snippet + "</br>"
            + data.news.entry_news_item_url;
        }
        request.send();
    }

在Python代码中,只需从请求字符串中收集get参数,如下所示:

# Add the request parameter to the function
def index(request):
    NewsFeed = feedparser.parse("https://trends.google.com.tr/trends/trendingsearches/daily/rss?geo=TR")
    # Get the parameter from request
    # By using get function if you do not have a parameter with given key it will return None 
    entry_id = request.GET.get('entry')
    if entry_id:
        entry = NewsFeed.entries[entry_id]

        return {"news" : {"Status" : "OK",
                          "item" : entry['title'],
                          "entry_news_item_title" : entry['ht_news_item_title'],
                          "entry_news_item_snippet" : entry['ht_news_item_snippet'],
                          "entry_news_item_url" : entry['ht_news_item_url']}}
    else:
        # Handle bad request
        return {"news":None}

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