用双字母打印单词会打印两次

Question

我试图打印有两个字母的单词，但它们打印了两次（尽管打印了正确的单词）。我做错了什么

phrase = "Donald hat seine Mutter gegessen"

for word in phrase.split():
    for letter in word:
        if letter + letter in word:
            print(word)

Answer 1

letter对phrase中的每一个word进行迭代，因此“t”和“s”出现两次，因此您会得到两次“Mutter”和“gegssen”

我的建议：使用列表保存结果，然后消除重复项：

phrase = "Donald hat seine Mutter gegessen"

#Start empty list
duplicate = []

for word in phrase.split():
    for letter in word:
        if letter + letter in word:
            duplicate.append(word) #Append the word

#Remove duplicates
duplicate = mylist = list(dict.fromkeys(duplicate))
print(duplicate)

产量：

['Mutter', 'gegessen']

Answer 2

只需每隔一秒搜索一个字母：

phrase = "Donald hat seine Mutter gegessen"

for word in phrase.split():
    for letter in word[::2]:
        if letter + letter in word:
            print(word)

或者最好在找到第一个双精度后添加一个中断：

phrase = "Donald hat seine Mutter gessgessen"

for word in phrase.split():
    for letter in word:
        if letter + letter in word:
            print(word)
            break

最终解决方案：

phrase = "test Aachen Mainschifffahrt Spaß test Aachen Mainschifffahrt Spaß"

sz_is_ss = True

s = set()
for word in phrase.split():
    for letter in word.lower()[::2]:
        if not word in s and (letter + letter in word.lower() or "ß" in word and sz_is_ss):
            s.add(word)
            print(word)
            break

印刷品：

 Aachen
 Mainschifffahrt
 Spaß

Answer 3

如果每个字母只有一次，则可以使用一组。您可以使用set(word)创建它。然后，如果字母中的^{}重复两次，则打印该单词

for word in phrase.split():
    if any(letter + letter in word for letter in set(word)):
        print(word)

要使此不区分大小写，请应用lower

for word in phrase.split():
    if any(letter + letter in word.lower() for letter in set(word.lower())):
        print(word)