如何在返回字符串列表中添加单词“and”

Question

我要把权利拿出来：

需要我的输出看起来像这样：

本周的7个视觉词汇是新的，谷仓，鲨鱼，货舱，艺术，只有，和眼睛。 本周的两个单词是减法、和加法。 本周的9个单词是：女孩、房子、最好的、东西、简单、错误、正确、再次、和上面的。 本周唯一的词汇是疑问。 本周没有新的视觉词汇

但我想知道在报税表中最后一个字之前的“和”。这是否恰当

这是代码：

wordlist = [['new', 'barn', 'shark', 'hold', 'art', 'only', 'eyes'],
            ['subtract', 'add'],
            ['girl', 'house', 'best', 'thing', 'easy', 'wrong', 'right', 'again', 'above'],
            ['question'],
            []]

def createSentence(wordlist):
    if len(wordlist) > 1:
        wordlist[-1] = "and " + wordlist[-1]
        return f'The {len(wordlist)} sight words for this week are {", ".join(wordlist)}.'
    elif len(wordlist) == 1:
        return f'The only sight word for this week is {wordlist[0]}.'
    elif len(wordlist) == 0:
        return 'There are no new sight words for this week!'

for lst in wordlist:
    print(createSentence(lst))

Answer 1

听起来像是要将"and "添加到数组/列表中最后一个元素的开头，但前提是您有多个单词

Python有一种非常简单的方法来获取数组/列表的最后一个元素

wordlist[-1]

在前面加上“和”：

wordlist[-1] = "and " + wordlist[-1]

最终的代码应该是这样的

def createSentence(wordlist):
    if len(wordlist) > 1:
        wordlist[-1] = "and " + wordlist[-1]
        return f'The {len(wordlist)} sight words for this week are {", ".join(wordlist)}.'
    elif len(wordlist) == 1:
        return f'The only sight word for this week is {wordlist[0]}.'
    elif len(wordlist) == 0:
        return 'There are no new sight words for this week!'

Answer 2

您可以将第一个n-1元素与, 连接起来，并在末尾添加and nth element：

if len(wordlist) > 1:
    return f'The {len(wordlist)} sight words for this week are {", ".join(wordlist[:-1])} and {wordlist[-1]}.'

这样您就不需要在输入列表的最后一个单词之前手动添加and

Answer 3

case handling than 1 list元素只需将除最小元素外的所有元素与','连接，然后添加最后一个元素：

wordlist = [['new', 'barn', 'shark', 'hold', 'art', 'only', 'and eyes'],
            ['subtract', 'and add'],
            ['girl', 'house', 'best', 'thing', 'easy', 'wrong', 
             'right', 'again', 'and above'],
            ['question'],
            []]

def createSentence(wordlist):
    if len(wordlist) > 1:
        return (f'The {len(wordlist)} sight words for this week are'
                f' {", ".join(wordlist[:-1])} {wordlist[-1]}.')
    elif len(wordlist) == 1:
        return f'The only sight word for this week is {wordlist[0]}.'
    elif len(wordlist) == 0:
        return 'There are no new sight words for this week!'

for lst in wordlist:
    print(createSentence(lst))

输出：

The 7 sight words for this week are new, barn, shark, hold, art, only and eyes.
The 2 sight words for this week are subtract and add.
The 9 sight words for this week are girl, house, best, thing, easy, wrong, right, again and above.
The only sight word for this week is question.
There are no new sight words for this week!

如果不想将'and '添加到输入中，请将其（包括逗号）放入格式字符串中：

wordlist = [['new', 'barn', 'shark', 'hold', 'art', 'only','eyes'],
            ['subtract', 'add'],
            ['girl', 'house', 'best', 'thing', 'easy', 'wrong', 'right', 'again','above'],
            ['question'],
            []]

def createSentence(wordlist):
    if len(wordlist) > 1:
        return (f'The {len(wordlist)} sight words for this week are ' 
                f'{", ".join(wordlist[:-1])}, and {wordlist[-1]}.')
    elif len(wordlist) == 1:
        return f'The only sight word for this week is {wordlist[0]}.'
    elif len(wordlist) == 0:
        return 'There are no new sight words for this week!'

for lst in wordlist:
    print(createSentence(lst))

以获得与上述完全相同的输出

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您可以使用列表切片。更多信息：Understanding slice notation