将“in list”放入if语句

Question

我目前正在制作一个刽子手游戏。我的问题在第二个for循环中，对于单词列表中的x。这个for循环应该经过单词列表（在本例中为['H'，'E'，'L'，'L'，'O']），并且：

if x in newwordlist or x==guessedletter，然后将x打印到新列表上

elif x not in newwordlist or x!=guessed letter，然后为该值打印一个“-”

当我在控制台中键入字母H作为猜测字母时。 newwordlist将更新并成为['H'、'-'、'-'、'-'、'-'、'-']，因为我在代码中指定了如果x=guessedletter，则打印

但是，当我继续进行下一个输入时，比如O。newwordlist现在是['-'，'-'，'-'，'-'，'-'，'O']。 我如何使它变成['H'，'-'，'-'，'-'，'-'，'-'，'O']

My for循环指定如果x在newwordlist中，则打印它，如果不是，则不打印“-”。为什么不记得newwordlist包含值H，不应该用破折号替换。它应该打印该值

ALPHABET = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U',
            'V', 'W', 'X', 'Y', 'Z']

word = input()  # word player 2 is trying to guess
wordlist = list(word)  # word in list form
guessedletter = input()  # guessed letter
guesses = 6  # max amount of guesses

while guesses <= 6 and guesses > 0:
    newABC = []
    newABCstring = ('')
    for x in ALPHABET:
        if x != guessedletter:
            newABC.append(x)
            newABCstring = (newABCstring + str(x))
    print("Unused letters:" + " " + (newABCstring))
    ALPHABET = newABC

    newwordlist = []

    for x in wordlist:  # ['H', 'E', 'L', 'L', 'O']
        if x in newwordlist or x == guessedletter:
            newwordlist.append(x)
        elif x not in newwordlist or x != guessedletter:
             newwordlist.append('-')  # ['-', '-', 'L', 'L', '-']
    print(newwordlist)

    newwordliststring = ('')
    for x in newwordlist:
        newwordliststring = (newwordliststring + str(x))
        if len(newwordliststring) == len(newwordlist):
            print("Guess the word," + " " + (newwordliststring))  # prints the guessedletter+dashes in string form


    guessedletter = input()

   

Answer 1

您可能希望尝试此方法并将其与您的进行比较：

class E(Exception): pass

A = []

for i in range(65, 91):
    A.append(chr(i))

w = []

for i in 'HELLO':
    w.append(i)

g = ['-'] * len(w)
d = {}

for i in w:
    d[i] = 0

print('Please guess the word :\n%s\n' % g)
while True:
    try:
        i = input('Guess letter/word: ').upper()
        if __debug__:
            if len(i) != 1 and i not in A:
                raise AssertionError('Only a single letter and ASCII permitted')
            else: raise E
    except AssertionError as e:
        print('\n%s' % e.args[0])
        continue

    except E:
        if i in w:
            if i not in g:
                g[w.index(i, d[i])] = i
                d[i] = w.index(i)
                print(g)
            else:
                try:
                    g[w.index(i, d[i]+1)] = i
                    d[i] = w.index(i, d[i]+1)
                    print(g)
                except ValueError:
                    continue

        if w == g:
            print('You are great')
            break

输出：

PS D:\Python> python p.py
Please guess the word :
['-', '-', '-', '-', '-']

Guess letter/word: h
['H', '-', '-', '-', '-']
Guess letter/word: e
['H', 'E', '-', '-', '-']
Guess letter/word: l
['H', 'E', 'L', '-', '-']
Guess letter/word: l
['H', 'E', 'L', 'L', '-']
Guess letter/word: l
Guess letter/word: l
Guess letter/word: o
['H', 'E', 'L', 'L', 'O']
You are great

Answer 2

您应该执行以下操作

1. 将newwordlist放置在while循环之外
2. 只需在for循环中替换newwordlist的索引。 请参阅下面的代码

`

ALPHABET = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U',
            'V', 'W', 'X', 'Y', 'Z']

word = input()  # word player 2 is trying to guess
wordlist = list(word)  # word in list form
guessedletter = input()  # guessed letter
guesses = 6  # max amount of guesses

#define the newwordlist outside while loop
newwordlist = ['-' for letter in word]
while guesses <= 6 and guesses > 0:
    newABC = []
    newABCstring = ('')
    for x in ALPHABET:
        if x != guessedletter:
            newABC.append(x)
            newABCstring = (newABCstring + str(x))
    print("Unused letters:" + " " + (newABCstring))
    ALPHABET = newABC

#     newwordlist = []

    for index, x in enumerate(wordlist):  # ['H', 'E', 'L', 'L', 'O']
        if x in newwordlist or x == guessedletter:
            #just replace the value in the newwordlist
            newwordlist[index] = x  
            #blow elif is not required
#         elif x not in newwordlist or x != guessedletter:
#              newwordlist.append('-')  # ['-', '-', 'L', 'L', '-']
    print(newwordlist)

    newwordliststring = ('')
    for x in newwordlist:
        newwordliststring = (newwordliststring + str(x))
        if len(newwordliststring) == len(newwordlist):
            print("Guess the word," + " " + (newwordliststring))  # prints the guessedletter+dashes in string form


    guessedletter = input()

`

Answer 3

对于while循环中的每个迭代，都会执行“newwordlist=[]”。因此，即使在上一次迭代中设置了“H”，也会将其重置为[]

在while循环之外，可以有一个newwordlist，其中元素被初始化为“-”。每当玩家猜对字母时，只需更新该列表，而不是在列表中添加元素

newwordlist = ['-' for x in wordlist]
while guesses > 0:
    # some code
    for idx, letter in enumerate(wordlist):
        if letter == wordlist[idx]:
            newwordlist[idx] = letter
    print(newwordlist)
    # remaining code