合并与比较

Question

有一个包含以下文件的目录：

ab_list
bd_list
cd_list
mno_list
hk_list 
pd_list

我有另一个名为testfile的文件，位于该目录之外，如下所示：

abc
que nw

ab_list   ON   8
gs_list   ON   9
hk_list   OFF  9
bd_list   ON   7
cd_list   OFF  6
fr_list   ON   5
mno_list  ON   4
pq_list   OFF   6
jk_list   ON   7
pd_list   OFF  8

我想比较2和所有文件名为的文件，在它旁边（如果匹配），它们的内容应该合并到一个名为merge_file的新文件中。与testfile匹配但已关闭的其他文件，其文件名应打印在新的_文件中。 ab_列表bd_列表和mno_列表的内容应合并到top_文件中 输出应该是 新文件：

cd_list OFF no.of lines in file
pd_list OFF no.of lines in file
hk_list OFF no. of lines in file
merge_file (this has all ON merged) no.of lines in file

以下是到目前为止的代码：

from pathlib import Path

with open('testfile') as fp:
    data = dict([tuple(line.split())for line in fp if line.strip()])

with open('merge_file', 'w') as merge_file, open('match_file', 'w') as match_file:
    lines = 0
    for fp in Path(r'./test').glob('*_list'):
        if fp.name in data:
            if data[fp.name] == 'ON':
                content = fp.open().readlines()
                lines += len(content)

                merge_file.write('\n'.join(content) + '\n')
            else:
                content = fp.open().readlines()
                match_file.write(fp.name + ' OFF {}\n'.format(len(content)))
    match_file.write('merge_file (this has all ON merged) {}'.format(lines))

我想从第一行读取，但它给出了一个称为索引错误的错误：列表超出范围。当前代码从第4行读取

Answer 1

假设目录名为Folder，并且在该目录中有另一个名为folder的目录，此代码只执行以下操作：

from glob import glob

test_file_directory = "C:\\Users\\User\\Desktop\\Folder\\"

files1 = glob("*.txt")
with open(test_file_directory+"testfile.txt","r") as f:
    files2 = [' '.join([l.split()[0],l.split()[1]]) for l in f.readlines()[3:]]

for f1 in files1:
    for f2 in files2:
        if f1[:-4]+'   ON' == f2:
            #print('match')
            with open('merge_file.txt','a') as a:
                with open(f1,'r') as r:
                    a.write(r.read()+'\n')
        elif f1[:-4]+'   OFF' == f2:
            #print('match')
            with open('match_file.txt','a') as a:
                with open(f1,'r') as r:
                    a.write(f"{f2} {len(r.readlines())}\n")