TypeError:“非类型”对象在Tkinter中不可调用

Question

您好，我是tkinter新手，正在尝试一个简单的tkinter GUI，但出现错误：

TypeError: 'NoneType' object is not callable

这是我的代码：

from tkinter import *
from tkinter import filedialog
import pandas as pd
import pyodbc
from sqlalchemy import create_engine
import urllib

master = Tk()
master.title("Demo GUI")
master.geometry("900x400+150+150")
master.resizable(0,0)

def browse_file():
    global file_path
    global data_frame
    file_path = filedialog.askopenfilename(title = "Choose the file to upload")
    data_frame = pd.read_excel(file_path)

Label = Label(master,text="Choose the file to upload").grid(row=0)

Button = Button(master,text='Browse',command = browse_file).grid(row=0,column=1,pady=4)

Label_1 = Label(master,text="The file selected: "+file_path).grid(row=1,column=0)

master.mainloop()

我得到的错误是

TypeError                                 Traceback (most recent call last)
<ipython-input-29-451372edd65a> in <module>
     25 Button = Button(master,text='Browse',command = browse_file).grid(row=0,column=1,pady=4)
     26 
---> 27 Label1 = Label(master,text="The file Choosen: "+file_path).grid(row=1,column=0)
     28 
     29 

TypeError: 'NoneType' object is not callable

Answer 1

您所犯的错误是输入错误：通过书写：

Label = Label(master,text="Choose the file to upload").grid(row=0)

将grid调用的结果分配给原始的tk.Label类型（Label）。网格返回调用为None

因此，当您尝试创建Label1时，实际上是在调用Label，现在是None

只需将该行替换为：

 l = Label(master,text="Choose the file to upload")
 l.grid(row=0)

或者干脆

Label(master,text="Choose the file to upload").grid(row=0)

Answer 2

这就是答案：

from tkinter import *
from tkinter import filedialog
import tkinter as tk
import pandas as pd
import pyodbc
from sqlalchemy import create_engine
import urllib

master = Tk()
master.title("Demo GUI")
master.geometry("900x400+150+150")
master.resizable(0,0)

def browse_file():
    global file_path
    global data_frame
    file_path = filedialog.askopenfilename(title = "Choose the file to upload")
    data_frame = pd.read_excel(file_path)

Label = Label(master,text="Choose the file to upload").grid(row=0)

Button = Button(master,text='Browse',command = browse_file).grid(row=0,column=1,pady=4)

Label_1 = tk.Label(master,text="The file selected: "+file_path).grid(row=1,column=0)

master.mainloop()

Answer 3

“NoneType”对象不可调用错误是由于将对象放置在定义的位置引起的。 所以不是

Label_1 = Label(master,text="The file selected: "+file_path).grid(row=1,column=0)

尝试：

Label(master,text="The file selected: "+file_path).grid(row=1,column=0)

或

Label_1 = Label(master,text="The file selected: "+file_path)
Label_1.grid(row=1,column=0)

也不要使用Button=Button（master…），而是为变量指定一个唯一的名称