Djang中ModelAdmin的标签名称

Question

如何给这个类一个在后端显示的标签而不是“EditedAddress”？在

class EditedAddressAdmin(admin.ModelAdmin):
    list_display = ('comp_name','fam_name', 'fon')
    search_fields = ['fam_name','comp_name']


admin.site.register(EditedAddress,EditedAddressAdmin)

Answer 1

您可以通过在模型中添加“详细名称”和/或“详细名称”复数形式来调整模型名称的显示方式：

class EditedAddress(models.Model):
    class Meta:
        verbose_name = 'Edited Address'
        verbose_name_plural = 'Edited Addresses'