擅长:python、mysql、java
<p>我决定创建两个列表,一个是信用=0,一个是信用=1的客户</p>
<pre class="lang-py prettyprint-override"><code>cred=[]
i0=[]
i1=[]
#df.hist(column='installment',bins='auto',label='credit=1',alpha=0.5,color='blue')
#df.hist(column='credit.policy',bins='auto',label='credit=1',alpha=0.5,color='red')
for i, row in credit.iteritems():
cred.append(row)
for i, row in ins.iteritems():
if cred[i]==1:
i1.append(row)
else:
i0.append(row)
plt.hist(i0,bins=75,color='blue',label='credit=0')
plt.hist(i1,bins=75,alpha=0.5,color='red',label='credit=1')
plt.legend()
plt.show()
</code></pre>
<p><a href="https://i.stack.imgur.com/NTMyn.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/NTMyn.png" alt="image"/></a></p>