提交表单时返回到？第1页（使用Flask）的干净方式

Question

我的模板中有一个表单，在提交时为我的数据库查询提供搜索过滤器。否则，查询将返回所有文档。我正在使用flask paginate导航结果

我的错误是，如果用户提交表单时在第2页，则该页会重新加载第2页，并显示新查询的结果，即使返回的文档数不超过1页。在这种情况下，加载的页面为空，没有分页链接可导航回第1页。到目前为止，我已经通过在提交表单时将flask paginate的“page”变量的值更改为等于1半解决了这个问题。现在它似乎加载了第1页的结果，当我打印（第页）时，它正确地打印了“1”。但是，url中的查询字符串仍然显示？page=2。因此，我正在寻找一个更清洁的解决方案？还是清除查询字符串的方法

    @app.route("/thingstodo/<city>", methods=["GET", "POST"])
def suggestion_list(city):
    form = FilterResultsForm()
    cities = mongo.db.cities
    page, per_page, offset = get_page_args(
        page_parameter="page", per_page_parameter="per_page"
    )
    print(page) 
    if form.validate_on_submit():
        page = 1
    per_page = 3
    offset = (page - 1) * per_page
    query = ""
    if form.validate_on_submit() or "filters" in session:
        filters = (
            form.category.data if form.category.data else session["filters"]
        )
        session["filters"] = filters
        array = []
        for filter in filters:
            newdict = {}
            newdict["thingsToDo.category"] = filter
            array.append(newdict)
        query = cities.aggregate(
            [
                {"$unwind": "$thingsToDo"},
                {"$match": {"location": city, "$or": array}},
                {
                    "$lookup": {
                        "from": "users",
                        "localField": "thingsToDo.author",
                        "foreignField": "username",
                        "as": "user_profile",
                    }
                },
                {"$unwind": "$user_profile"},
                {
                    "$project": {
                        "suggestion": "$thingsToDo.suggestion",
                        "cost": "$thingsToDo.cost",
                        "category": "$thingsToDo.category",
                        "url": "$thingsToDo.url",
                        "comment": "$thingsToDo.comment",
                        "author": "$user_profile.username",
                        "profile": "$user_profile.picture",
                    }
                },
            ]
        )
    else:
        query = cities.aggregate(
            [
                {"$match": {"location": city}},
                {"$unwind": "$thingsToDo"},
                {
                    "$lookup": {
                        "from": "users",
                        "localField": "thingsToDo.author",
                        "foreignField": "username",
                        "as": "user_profile",
                    }
                },
                {"$unwind": "$user_profile"},
                {
                    "$project": {
                        "suggestion": "$thingsToDo.suggestion",
                        "cost": "$thingsToDo.cost",
                        "category": "$thingsToDo.category",
                        "url": "$thingsToDo.url",
                        "comment": "$thingsToDo.comment",
                        "author": "$user_profile.username",
                        "profile": "$user_profile.picture",
                    }
                },
            ]
        )
    results = list(query)
    total = len(results)
    suggestions = results[offset: offset + per_page]
    pagination = Pagination(
        page=page, per_page=per_page, total=total, css_framework="bootstrap4"
    )
    return render_template(
        "thingstodo.html",
        city=city,
        things=suggestions,
        page=page,
        per_page=per_page,
        pagination=pagination,
        form=form,
        title="Things to do",
    )