获取PID控制器的最后一个错误

2024-05-16 17:57:47 发布

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我试图在Python上构建一个PID控制器。下面是到目前为止我的实现。虽然语法是连贯的,但这仍然是伪代码

    def PID(self, Kp, Ki, Kd, reference_velocity, vehicle_velocity, current_time, last_update_time):
        desired_velocity = 0
        Kp = 0
        Ki = 0
        Kd = 0
        error = reference_velocity - vehicle_velocity
        delta_time = current_time - last_update_time

        proportional = Kp * error
        integral = Ki * error
        derivative = Kd * ((error - last_error) / (delta_time))

        desired_velocity = proportional + integral + derivative

        return desired_velocity

我试图通过我在这里已经给出的内容来理解last_error,但我无法理解


Tags: timeupdateerrorcurrentpidkdlastdelta
1条回答
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1楼 · 发布于 2024-05-16 17:57:47

将错误或最后一个错误存储在函数外部作用域的容器中

errors = []
def PID(...):
    ...
    errors.append(error)
    return desired_velocity

然后,在函数中,可以使用检索最后一个错误

...
last_error = errors[-1]

或者,您可以使控制器成为一个类,其实例由常量和起始参数初始化,并保留过去错误的记录(类似列表的容器)。电流/next输出控制信号的计算将是一种可使用电流参数值调用的方法

使用你的算法——类似这样的

class PID:
    def __init__(self,setpoint,t_now,Kp=0,Ki=0,Kd=0):
        self.setpoint = setpoint
        self.t_last = t_now
        self.Kp = Kp
        self.Ki = Ki
        self.Kd = Kd
        self.last_error = 0
    def adjust(self,process,t_now):
        error = process - self.setpoint
        delta_time = t_now - self.t_last

        proportional = self.Kp * error
        integral = self.Ki * error
        derivative = self.Kd * ((error - self.last_error) / (delta_time))

        desired_process = proportional + integral + derivative
        self.t_last = t_now
        self.last_error = error
        return desired_process

用法:

v_controller = PID(setpoint=66, t_now=0, Kp=.2, Kd=.1, Ki=1)
# or
#parameters = {'setpoint':66, 't_now':0, 'Kp':.2, 'Kd':.1, 'Ki':1}
#v_controller = PID(**parameters)

print(v_controller.adjust(66.1,1))
print(v_controller.adjust(66.2,2))
print(v_controller.adjust(65.9,3))
print('      -')
parameters = {'setpoint':66, 't_now':0, 'Kp':.2, 'Kd':.1, 'Ki':1.5}
v_controller = PID(**parameters)
print(v_controller.adjust(66.1,1))
print(v_controller.adjust(66.2,2))
print(v_controller.adjust(65.9,3))
print('      -')
parameters = {'setpoint':66, 't_now':0, 'Kp':1.25, 'Kd':.2, 'Ki':.5}
v_controller = PID(**parameters)
print(v_controller.adjust(66.1,1))
print(v_controller.adjust(66.2,2))
print(v_controller.adjust(65.9,3))

结果

>>> 
0.12999999999999262
0.2500000000000043
-0.1499999999999929
      -
0.17999999999998975
0.3500000000000057
-0.19999999999999005
      -
0.1949999999999889
0.37000000000000666
-0.2349999999999895
>>>

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