如何使用python以特定频率触发事件

Question

我想以特定频率触发事件，例如44100hz。
我希望下面的代码每秒执行“print”44100次，但事实并非如此

import time

frequency = 44100
desired_interval = 1 / frequency

events = 0

time_now = time.time()
time_end = time_now +1

while time_now < time_end:

    events += 1
    print(events)

    # some time has passed, sleep for desired interval less passed time
    if( desired_interval > ( time.time() - time_now ) ):
        time.sleep( desired_interval - ( time.time() - time_now ) )

    time_now = time.time()    

Answer 1

这更接近，即使“打印”事件很可能（非常肯定）不是以固定频率触发的

import time

frequency = 44100
desired_interval = 1 / frequency

events = 0

time_now = time.time()
time_start = time_now
time_end = time_now +1

while time_now < time_end:

    events += 1
    print(events)

    if( desired_interval * events > ( time.time() - time_start ) ):
        # abs mitigate the fact that sometime the result is negative.
        time.sleep( abs( desired_interval * events - ( time.time() - time_start ) ) )


    time_now = time.time()