我想scipy.interpolate可能坏了，还是我用错了？

Question

我正在处理一些缺失值的地理数据，并试图沿着它们的路径估算缺失值。我已经使用插值来处理其他值，包括我在这里包含的一组纬度（working_x）和经度（working_y）。但是，以下由断开x和断开y组成的数据会导致错误

from scipy import interpolate

working_x = [50.2577, 50.0482, 50.0486, 51.7697, 54.5125, 56.6626, 59.1144, 61.2571, 65.0806, 66.541, 68.8, 70.672, 72.5613, 74.7929, 75.7798, 78.119, 79.4935, 82.3863, 85.0249, 88.0613, 91.878, 94.1954, 96.7093, 98.3678, 100.5983, 102.5626]
working_y = [27.1174, 26.9498, 26.9501, 27.0585, 26.1905, 26.3719, 24.5836, 23.4857, 21.4881, 20.4295, 18.0235, 16.0258, 13.9794, 11.0714, 9.0558, 6.7257, 6.0434, 5.6889, 5.7001, 5.6913, 5.7709, 6.167, 5.7973, 4.9382, 3.1171, 1.7426]
broke_x = [50.3603, 50.2219, 50.2246, 50.182, 50.182, 50.182, 52.0052, 54.3371, 56.7533, 58.8949, 65.2883, 67.1264, 68.3829, 70.0129, 72.003, 73.8859, 75.1131, 75.6843, 77.3321, 78.6119, 81.6834, 83.8053, 87.7575, 89.1056, 92.7804, 95.1509, 100.2694, 101.2058]
broke_y = [27.0834, 26.678, 26.6786, 26.6716, 26.6716, 26.6716, 27.0163, 26.2115, 26.2435, 25.1276, 24.7504, 23.3715, 21.7267, 19.6113, 17.2461, 13.7936, 10.9089, 9.8805, 7.5112, 6.6072, 5.8491, 6.1449, 6.5355, 6.5364, 6.316, 6.1539, 3.4317, 2.6727]
tck1, u1 = interpolate.splprep([working_x, working_y], s=1)
tck, u = interpolate.splprep([broke_x, broke_y], s=1)

每当我运行上述代码时，都会出现此错误

ValueError                                Traceback (most recent call last)
<ipython-input-232-cad98765c4aa> in <module>
      6 broke_y = [27.0834, 26.678, 26.6786, 26.6716, 26.6716, 26.6716, 27.0163, 26.2115, 26.2435, 25.1276, 24.7504, 23.3715, 21.7267, 19.6113, 17.2461, 13.7936, 10.9089, 9.8805, 7.5112, 6.6072, 5.8491, 6.1449, 6.5355, 6.5364, 6.316, 6.1539, 3.4317, 2.6727][:10]
      7 tck1, u1 = interpolate.splprep([working_x, working_y], s=1)
----> 8 tck, u = interpolate.splprep([broke_x, broke_y], s=1)

C:\ProgramData\Anaconda3\envs\geo\lib\site-packages\scipy\interpolate\fitpack.py in splprep(x, w, u, ub, ue, k, task, s, t, full_output, nest, per, quiet)
    155     """
    156     res = _impl.splprep(x, w, u, ub, ue, k, task, s, t, full_output, nest, per,
--> 157                         quiet)
    158     return res
    159 

C:\ProgramData\Anaconda3\envs\geo\lib\site-packages\scipy\interpolate\_fitpack_impl.py in splprep(x, w, u, ub, ue, k, task, s, t, full_output, nest, per, quiet)
    278     iwrk = _parcur_cache['iwrk']
    279     t, c, o = _fitpack._parcur(ravel(transpose(x)), w, u, ub, ue, k,
--> 280                                task, ipar, s, t, nest, wrk, iwrk, per)
    281     _parcur_cache['u'] = o['u']
    282     _parcur_cache['ub'] = o['ub']

ValueError: Invalid inputs. ```

Answer 1

您的broke列表包含连续的相同点，显然interpolate.splprep()无法处理这些点。下面是一个突出问题的最小示例：

from scipy import interpolate

working_x = [1, 2, 3, 4]
working_y = [1, 2, 3, 4]

tck1, u1 = interpolate.splprep([working_x, working_y], s=1)

工作，而

broke_x = [1, 2, 3, 3] 
broke_y = [1, 2, 3, 3]

tck, u = interpolate.splprep([broke_x, broke_y], s=1)

抛出错误