Flask表单选择字段

2024-04-25 01:45:05 发布

您现在位置:Python中文网/ 问答频道 /正文

我的app.py如下所示:

from flask import Flask,render_template,url_for,request
from flask_bootstrap import Bootstrap
from wtforms import SelectField
from flask_wtf import FlaskForm

app = Flask(__name__)
Bootstrap(app)


def Form(FlaskForm):
    panel_brand = SelectField('Panel Brand',choices=[('tr','trina'),('lo','longi'), ('ph','phono'), ('leap','leapton')])
    mounting = SelectField('Mounting',choices=[('tr','trina'),('lo','longi'), ('ph','phono'), ('leap','leapton')])
    inverter = SelectField('inverter',choices=[('Fronius10','Fronius 10'),('Fronius5','Fronius 5'), ('huawei6','huawei 6'), ('huawei8','huawei 8') , ('SolarEdge125','SolarEdge 12,5')])
    order_fulfillment = SelectField('orderfulfillment',choices=[('all3','Panels + inverter + mounting'),('Panels','Panels'),('panelsinv','Panels + Inverter'),('installer','By Installer')])


@app.route('/', methods=['GET','POST'])
def index():
    form = Form(FlaskForm)
    return render_template('index.html', form=form)
if __name__ == '__main__':
    app.run(debug=True)

我的index.html如下所示

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <meta http-equiv="X-UA-Compatible" content="ie=edge">
    <title>Document</title>
</head>
<body>
    <form method="POST">
        {{ form.csrf_token }}
        {{ form.panel_brand }}
        {{ form.mounting }}
        {{ form.inverter }}
        {{ form.order_fulfillment }}
    <input type="submit">
    </form>
</body>
</html>

当我运行app.py文件时,它只显示submit按钮,而不是预期的下拉列表panel_brandmountinginverterorder_fulfillment,其中包含后续值。我想我在index()函数中缺少了一些调用ID?我不知道如何在正确的语法中做到这一点。有人能帮我吗


Tags: namefromimportformappflaskindexhtml
2条回答

您的代码有一个函数,它需要有一个类

改变

def Form(FlaskForm):
...
form = Form(FlaskForm)

class Form(FlaskForm)
...
form = Form(request.form)

似乎您的form声明正在子类化另一个对象

尝试:

def index():
    form = Form(request.form)

相关问题 更多 >