哨兵。HTTP状态200正常：API响应无效。JSON解码失败

Question

我一直试图用python通过Sentinel2API获取数据，但无法通过geojson格式获取数据。它不断地抛出一个错误 “SentinelAPIError:HTTP状态200 OK:API响应无效。JSON解码失败。”

我彻底地遵循了文档，但还是不断地出现同样的错误。我可以获取点数据，但无法获取geojson数据

我将感谢你在这方面的帮助。下面是代码片段。 "

    if self.boundary.endswith('.geojson'):
        
        
        footprint = geojson_to_wkt(read_geojson(self.boundary))

        
        products = api.query(footprint,
                             
                     date=(self.start_date,self.end_date),

                     platformname = 'Sentinel-2',

                     cloud_cover= (0,self.cloud_cover))
        

        products_gdf = api.to_geodataframe(products)

"

这里是错误

/usr/local/lib/python3.6/dist-packages/sentinelsat/sentinel.py in _load_subquery(self, query, order_by, limit, offset)
    394             json_feed = response.json()["feed"]
--> 395             if json_feed["opensearch:totalResults"] is None:
    396                 # We are using some unintended behavior of the server that a null is

KeyError: 'opensearch:totalResults'
During handling of the above exception, another exception occurred:

SentinelAPIError                          Traceback (most recent call last)
4 fr
/usr/local/lib/python3.6/dist-packages/sentinelsat/sentinel.py in _load_subquery(self, query, order_by, limit, offset)
    401             total_results = int(json_feed["opensearch:totalResults"])
    402         except (ValueError, KeyError):
--> 403             raise SentinelAPIError("API response not valid. JSON decoding failed.", response)
    404 
    405         products = json_feed.get("entry", [])

SentinelAPIError: HTTP status 200 OK: API response not valid. JSON decoding failed.

多谢各位

Answer 1

您的.geojson文件似乎无法解码。 首先检查已创建文件的编码语言。如果这没用

检查您的.geojson格式是否与以下格式类似：

{ "type": "FeatureCollection", "features": [ { "type": "Feature", "properties": {}, "geometry": { "type": "Polygon", "coordinates": [ [ [ 23.642578125, 37.93553306183642 ], [ 23.8018798828125, 37.93553306183642 ], [ 23.8018798828125, 38.026458711461245 ], [ 23.642578125, 38.026458711461245 ], [ 23.642578125, 37.93553306183642 ] ] ] } } ] }

您可以在this页面中快速生成.geojson文件

Answer 2

我的问题是，我没有使用为API创建的正确变量。我写的self.cloud_cover本来应该是self.cloudcoverpercentage。我在文档中跳过了