with open("utf32le.file", "rb") as file:
beginning = file.read(4)
# The order of these if-statements is important
# otherwise UTF32 LE may be detected as UTF16 LE as well
if beginning == b'\x00\x00\xfe\xff':
print("UTF-32 BE")
elif beginning == b'\xff\xfe\x00\x00':
print("UTF-32 LE")
elif beginning[0:3] == b'\xef\xbb\xbf':
print("UTF-8")
elif beginning[0:2] == b'\xff\xfe':
print("UTF-16 LE")
elif beginning[0:2] == b'\xfe\xff':
print("UTF-16 BE")
else:
print("Unknown or no BOM")
简单的答案是:读取前4个字节并查看它们
不那么简单的答案是:
可能有些二进制文件似乎有BOM表,但它们仍然可能只是二进制文件,其中的数据意外地看起来像BOM表
除此之外,您通常也可以将没有BOM表的文本文件视为UTF-8
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