获取多行字符串中单词“print”的索引

Question

我试图找到多行文本中所有单词的索引：“print”。但也存在一些问题，这些问题是：

1. 如果一行中有两个打印，代码将两次返回单词“print”的相同索引
2. 它无法在同一行中找到第二个“打印”的索引，但会将第一个“打印”的索引打印两次。 我的代码是：

text = '''print is print as
it is the function an
print is print and not print
'''

text_list = []

for line in text.splitlines():

    #'line' represents each line in the multiline string
    text_list.append([])

    for letter in line:
        #Append the letter of each line in a list inside the the text_list
        text_list[len(text_list)-1].append(letter)

for line in text_list:
    for letter in line:

        #check if the letter is after 'p' is 'r' and after that 'i' and then 'n' and at last 't'
        if letter == "p":
            num = 1

            if text_list[text_list.index(line)][line.index(letter)+num] == 'r':
                num += 1
                
                if text_list[text_list.index(line)][line.index(letter)+num] == 'i':
                    num += 1

                    if text_list[text_list.index(line)][line.index(letter)+num] == 'n':
                        num += 1

                        if text_list[text_list.index(line)][line.index(letter)+num] == 't':
                            num += 1
                            print(f'index (start,end) = {text_list.index(line)}.{line.index(letter)}, {text_list.index(line)}.{line.index(letter)+num}')
                        

当我运行它时，会打印：

index (start,end) = 0.0, 0.5 #returns the index of the first 'print' in first line
index (start,end) = 0.0, 0.5 #returns the index of the first 'print' in first line instead of the index of the second print
index (start,end) = 2.0, 2.5 #returns the index of the first 'print' in third line
index (start,end) = 2.0, 2.5 #returns the index of the first 'print' in third line instead of the index of the second print
index (start,end) = 2.0, 2.5 #returns the index of the first 'print' in third line instead of the index of the third print

您可以看到，在结果中，索引是重复的。这是文本列表：

>>> text_list
[['p', 'r', 'i', 'n', 't', ' ', 'i', 's', ' ', 'p', 'r', 'i', 'n', 't', ' ', 'a', 's'],
['i', 't', ' ', 'i', 's', ' ', 't', 'h', 'e', ' ', 'f', 'u', 'n', 'c', 't', 'i', 'o', 'n', ' ', 'a', 'n'],
['p', 'r', 'i', 'n', 't', ' ', 'i', 's', ' ', 'p', 'r', 'i', 'n', 't', ' ', 'a', 'n', 'd', ' ', 'n', 'o', 't', ' ', 'p', 'r', 'i', 'n', 't']]
>>>

文本列表中的每个列表都是文本中的一行。有三行，因此在文本列表中有三个列表。如何获取第一行中第二个“打印”的索引以及第三行中第二个和第三个“打印”的索引？您可以看到，它只返回第一行和第三行中第一个“print”的索引

Answer 1

您可以使用正则表达式：

import re

text = '''print is print as
it is the function an
print is print and not print
'''

for i in re.finditer("print", text):
    print(i.start())

# OR AS A LIST

[i.start() for i in re.finditer("print", text)]