我需要处理大量的数据行,只有异步处理才有意义
我需要查看列表处理状态,即Done processing 1/3
,但当我增加计数器时,它始终保持在1。这是有意义的,因为我将计数器发送到函数中。我需要这样做,因为如果没有它,我会:
UnboundLocalError: local variable 'processed' referenced before assignment
使用Python 3.8
任何帮助都将不胜感激
这里有一个测试链接:https://ideone.com/gRjrf2
我将代码抽象如下:
import os, logging
import asyncio
logging.basicConfig(level=logging.INFO, format='%(asctime)s %(levelname)-8s [%(filename)s:%(lineno)d] %(message)s', datefmt='%d-%b-%y %H:%M:%S')
logger = logging.getLogger(__name__)
items = [{"name": "A"}, {"name": "B"}, {"name": "C"}]
processed = 0
async def increment(item):
count = item.get('count', 0)
count += 1
return count
async def get_and_update(item, processed):
item['count'] = await increment(item)
# Show progress now, but how?
processed += 1
logger.info(f"You can't see me {processed}")
async def run():
logger.info(f"Processing {len(items)} items...")
await asyncio.gather(*[
asyncio.create_task(
get_and_update(item, processed)
) for item in items
])
loop = asyncio.get_event_loop()
loop.run_until_complete(run())
我得到的结果是:
28-Aug-20 11:19:22 INFO [prog.py:23] Processing 3 items...
28-Aug-20 11:19:22 INFO [prog.py:20] You can't see me 1
28-Aug-20 11:19:22 INFO [prog.py:20] You can't see me 1
28-Aug-20 11:19:22 INFO [prog.py:20] You can't see me 1
您的基本问题是,通过将
processed
声明为get_and_update
的参数,您正在隐藏全局processed
变量。您需要删除该参数,然后在该函数中将processed
声明为全局,如下所示:上面的输出是:
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