下面的(第一次尝试)脚本是对我的一个测试,如何使用一个函数的返回值作为另一个函数的输入值。 这很好: 用户可以选择D或W(存款/取款)。 saldo_实际值(目前)为1500。 出于评估原因,我在功能输入控制和功能财务操作之间打印(值)。 这些值确实在第二个函数中得到
带D、W的输入结果位于代码下方(以及TypeError)
然而!问题>&燃气轮机;如果输入为空5次,或给出了其他字母D或W,则名为:input_control的函数中作为输入的第一个值为None。这就产生了一个打字错误。我尝试了不同的方法,但我想不出解决办法。 希望你能帮助我。非常感谢!!你好,简
def input_control():
# Actuele saldo na inleg en opnemen. Begin saldo_actual = 1000 euro.
saldo_actual = 1500
# saldo_deposit om aan het einde de klant het totaal gestorte bedrag te laten weten.
saldo_deposit = 0
# saldo_withdrawel om aan het einde de klant het totaal opgenomen bedrag te laten weten.
saldo_withdrawel = 0
# amount_total het totale verschil tussen saldo_deposit en saldo_withdrawel, in euro's.
# amount_total wordt bij saldo_actual opgeteld (of afgetrokken.)
amount_total = 0
# empty_counter telt aantal keren dat het invoerveld leeg bleef PLUs de keren dat een foutief iets werd ingevoerd.
attemps = 5
# transactions_counter: aantal keren dat een transactie gedaan werd. Max = 5
transactions_counter = 0
# initieren van de mogelijkheid voor de klant om het programma te stoppen met een q of Q. stop.
stop = 'a'
# saldo_minimum is ondergrens >> zit je aan de grens kan je niet meer opnemen.
saldo_minimum = -1500
empty_counter = 0
letter_definitief = 'a'
while empty_counter < 6:
try:
if empty_counter == 5:
print("Je probeerde het 5 keer. Terminating Programm.")
break
letter_keuze= input('Wat wil je doen? Type D voor deponeren. W voor opnemen.')
if not letter_keuze:
print('niks ingevuld.')
print()
empty_counter = empty_counter + 1
continue
if letter_keuze.lower() != 'w' and letter_keuze.lower() != 'd':
print('Type een W of D of Q als keuze. Nu typte je iets anders')
print()
empty_counter = empty_counter + 1
continue
if letter_keuze.lower() == 'd' or letter_keuze.lower() == 'w':
letter_definitief = letter_keuze.lower()
return letter_definitief, saldo_actual
except TypeError:
print('it is a NoneTYpe')
break
value = input_control()
print(value)
letter_definitief = value[0]
saldo_actual = value[1]
def finance_actions(*args):
print(f'This is in finance_actions: {letter_definitief}.')
print(f'This is also in finance_actions {saldo_actual}.')
finance_actions(letter_definitief, saldo_actual)
W情况下的结果:
Choose D for Deposit and W for withdrawel.w
['w', 1500]
This is in finance_actions: w.
This is also in finance_actions 1500.
D情况下的结果:
Choose D for Deposit and W for withdrawel.d
['d', 1500]
This is in finance_actions: d.
This is also in finance_actions 1500.
5个空输入或5个其他字母的结果:
hoose D for Deposit and W for withdrawel.
There was nothing given in.
Choose D for Deposit and W for withdrawel.
There was nothing given in.
Choose D for Deposit and W for withdrawel.
There was nothing given in.
Choose D for Deposit and W for withdrawel.
There was nothing given in.
Choose D for Deposit and W for withdrawel.
There was nothing given in.
Choose D for Deposit and W for withdrawel.
You tried 5 times. Terminating Programm.
None
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-25-13cc824df307> in <module>
56 print(value)
57
---> 58 letter_definitief = value[0]
59 saldo_actual = value[1]
60
TypeError: 'NoneType' object is not subscriptable
如果
value
是None
,那么您不应该运行finance_actions
。替换此代码:使用此代码:
由于“value”的值为None,因此引发类型错误。 要避免出现此错误,请尝试-
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