在Python中创建“Typeracer”时出现问题

Question

我对编程相当陌生，从学习一些Python开始。我认为这将是一个有趣的挑战，创造一个游戏就像“Typeracer”，但只键入字母尽可能快。我用Tkinter为它构建了一个GUI。我刚开始检查用户输入是否等于字符串，然后使用以下代码显示他们赢了：

from tkinter import *
import time

key = "abcdefghijklmnopqrstuvwxyz"
start_time = time.time()


root = Tk()
root.title("ABC Game")

answer = Entry(root, width=50)
answer.grid(row=0, column=0)


def check_answer():
    if answer.get() == key:
        end_time = time.time()
        result_time = round(end_time - start_time, 3)
        label_won = Label(root, text="Correct! Your time was: " + str(result_time))
        label_won.grid(row=2, column=0)
    else:
        label_lost = Label(root, text="Incorrect")
        label_lost.grid(row=2, column=0)


answer_button = Button(root, text="Submit", command=check_answer)
answer_button.grid(row=1, column=0)


root.mainloop()

但后来我想挑战一下，要求用户输入与字母表中的下一个字母完全相等，不允许输入错误

我在这一点上有点卡住了，我的问题是我不知道如何编写只检查用户下一次输入的代码。如果它是预期的输入，那么做这个，否则做那个

from tkinter import *
import time

alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m",
            "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]

root = Tk()
root.title = "ABC Game"

game_running = False

#This is the part where I'm stuck, might be faults in the code at other places as well
def key_pressed(event):
    global pressed_key
    pressed_key = repr(event.char)
    n_keys_pressed = 0
    for letters in alphabet:
        while n_keys_pressed <= 28:
            if str(pressed_key) == alphabet[n_keys_pressed]:
                n_keys_pressed += 1
                print("You hit: " + repr(event.char))


def start_game():
    global game_running
    game_running = True
    start_time = time.time
    type_frame = Frame(root)


start_button = Button(root, text="Click me to start the timer", width=50, height=10, command=start_game)
start_button.grid(row=0, column=0)

entry = Entry(root, width=50)
entry.grid(row=1, column=0)

root.mainloop()

非常感谢您的任何帮助或提示！谢谢

Answer 1

您需要使用导入时间功能并键入time.timer（为计时需要多少秒）