如何使用Python从YAML中的特定键中删除值？

Question

我已经用Python成功地解决了在YAML中向键添加值的问题，并开始了与添加代码相反的工作。以下是我对代码工作方式的建议：

connected_guilds:
- 1
- 2

运行代码后，YAML文件应更改为：

connected_guilds:
- 1

这是我的代码，但是它不起作用，它最终完全消失了，剩下的是我随附的第一个YAML示例中的-1

with open('guilds.yaml', 'r+') as guild_remove:
    loader = yaml.safe_load(guild_remove)

    content = loader['connected_guilds']

    for server in content:
        if server != guild_id:
            continue
        else:
            content.remove(guild_id)

            guild_remove.seek(0)

            yaml.dump(content, guild_remove)

            guild_remove.truncate()

如果有人能帮助我，我将不胜感激

Answer 1

当Python已经向您提供以下内容时，不要尝试重新实现搜索要删除的项：

with open('guilds.yaml', 'r+') as guild_remove:
    content = yaml.safe_load(guild_remove)
    content["connected_guilds"].remove(guild_id)
    guild_remove.seek(0)
    yaml.dump(content, guild_remove)
    guild_remove.truncate()

Answer 2

以下是解决方案（参考添加代码）：

with open('guilds.yaml', 'r+') as guild_remove:
    loader = yaml.safe_load(guild_remove)

    content = loader['connected_guilds']

    for server in content:
        if server != guild_id:
            continue
        else:
            content.remove(guild_id)

            guild_remove.seek(0)

            yaml.dump({'connected_guilds': content}, guild_remove)

            guild_remove.truncate()