我正在尝试为对数表编写代码。输出应该是三行表示城市总数、唯一人口计数和第一位数频率分布,然后是三列表示数字、计数和百分比
这是我当前的代码:
def main():
population=set()
#declaring dictionary to hold the count of #each digit
digits={}
#initializing totCities to 0 that holds the count of total number of cities
totCities=0
#initializing all digits in the dictionary to 0
for i in range(1, 10):
num=str(i)
num=num[0]
digits[num]=0
#opening Census_2009.txt file
try:
infile=open("Census_2009.txt",'r')
#throwing error if file cannot be opened and exiting the program
except OSError:
print("Could not open file")
exit()
#ignoring the headernext(infile)
#iterating through each line in file
for i in infile:
#incrementing totCities for each city
totCities+=1
line=i.rstrip().split('\t')
#adding each population count to the set and incrementing the count of the first digit in #the dictionary
population.add(line[-1])
digits[line[-1][0]]+=1
#closing Census_2009.txt
fileinfile.close()
#opening benford.txt file to write the Output
outfile=open("benford.txt",'w')
print("Output written to benford.txt")
#writing the output to the file
outfile.write("Total number of cities: {}\n".format(totCities))
outfile.write("Unique population counts: {}\n".format(len(population)))
outfile.write("Digit\tCount\tPercentage\n")
for key, value in digits.items():
outfile.write("{}\t{}\t{}\n".format(key, value, round(((value/totCities)*100), 1)))
#closing benford.txt
fileoutfile.close()
main()
但是,我得到了这个错误:
File "<ipython-input-15-061b69b87f23>", line 28, in main
digits[line[-1][0]]+=1
KeyError: 'C'
你知道这个错误的具体用途吗?你知道如何修复它吗? 抱歉,代码太长了
正如其他人所指出的,
print(line[-1][0])
可能是给了你意想不到的东西,即'C'
而不是数字。我们看不到您的输入数据,很难知道这是数据不一致的问题,还是您选择了错误的字段如果您确信您的代码选择了正确的字段,但偶尔会忽略一行数据,那么您可以使用以下方法对该部分进行快速局部防弹:
一些其他未经请求的提示,接受或离开:
digits = dict((d, 0) for d in range(1, 10))
# digits will be {1: 0, 2: 0, 3: 0, 4: 0, 5: 0, 6: 0, 7: 0, 8: 0, 9: 0}
collections
模块有一个处理大多数用例的Counter
类李>祝你好运
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