我有一套摄像头,每个摄像头的URL都是RTSP格式的。我创建了一个小脚本来解析camera_config JSON文件中的摄像头URL,但现在我不知道如何将视频嵌入HTML页面上的网格布局中。我写的剧本:
import json
from flask import flask
data = request.get_json()
file = open('cam_config.json',)
data = json.load(file)
for i in data['camStreams']:
i = data['camUrl']
@app.route("/livecams")
def livecams():
return render_template("live_cams.html", camUrl = i)
JSON文件:
{
"camDataDir":"/e/camData",
"playback": {
"playbackSpeed":"16.0"
},
"camStreams": [
{
"camName":"driveway",
"camUrl":"rtsp://admin:gf2UYmfH2kZDyEU@192.168.1.107:554/Streaming/Channels/3",
"camUrl4k":"rtsp://admin:gf2UYmfH2kZDyEU@192.168.1.107:554/Streaming/Channels/1",
"camUrl720p":"rtsp://admin:gf2UYmfH2kZDyEU@192.168.1.107:554/Streaming/Channels/3",
"camUrlMjpeg":"http://admin:gf2UYmfH2kZDyEU@192.168.1.107/ISAPI/Streaming/channels/102/httpPreview"
}
},
{
"camName": "backyard",
"camUrl": "rtsp://admin:jA6CL3G7Nukj7ST@192.168.1.166/cam/realmonitor?channel=1&subtype=02",
"camUrl4k": "rtsp://admin:jA6CL3G7Nukj7ST@192.168.1.166/cam/realmonitor?channel=1&subtype=01",
"camUrl720p": "rtsp://admin:jA6CL3G7Nukj7ST@192.168.1.166/cam/realmonitor?channel=1&subtype=02",
"camUrlMjpeg": "http://admin:jA6CL3G7Nukj7ST@192.168.1.166/cgi-bin/mjpg/video.cgi?channel=0&subtype=1"
}
}
]
}
HTML页面(不完整)
{% extends "layout.html" %}
{% block content %}
<h1>Live Cams</h1>
<div class="grid"
<div class="container mt-3 mb-3">
<img src="{{ camUrl }}" alt="Cam 1" width="640" height="360">
</div>
{% endblock content %}
{% block script %}
{% endblock script %}
live_cams.html是用于实时摄像机镜头的页面。我如何修改它以读取每个URL并将其作为网格输出到HTML页面?实际上,我必须在HTML文件中硬编码每个摄像头,但我希望它在调用HTML文件时自动生成。其目的是简单地用额外的摄像头更新cam_配置,并让其动态更新
感谢任何能帮忙的人。烧瓶对我来说是新的
您可以将cam数据直接传递到
render_template
中,并使用jinja for循环输出camStreams
中每个对象的容器(或任何您想要的),例如:你的看法:
在html中:
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