如何使用OpenCV或numpy打印线上每个点的坐标？

Question

我使用下面的代码打印线上每个点的坐标

首先，我用两个坐标在黑色的2D平面上画了一条线

第二，我用两点的坐标来计算斜率和截距

第三，我在二维平面上打印直线上所有点的坐标

我认为我不够聪明，不能做这件事。虽然我能解决这个问题，但这不是一个容易的办法

我的代码：

import cv2
import numpy as np

y1=-304 #point1_y
y2=477 #point2_y
x1=-957 #point1_x
x2=883 #point2_x

img=np.zeros((300,300,3),np.uint8)
cv2.line(img,(x1,y1),(x2,y2),(0,255,0),3)
cv2.imshow('Result', img)
cv2.waitKey(0)
cv2.destroyAllWindows()

k=(y2-y1)/(x2-x1)
b = y1 - k*x1
for x in range(1,300):
    y=k*x+b
    print(x,y)

结果图像：

坐标信息：

1 102.62934782608696
2 103.05380434782609
3 103.47826086956522
4 103.90271739130435
5 104.32717391304348
6 104.75163043478261
7 105.17608695652174
8 105.60054347826087
9 106.025
10 106.44945652173914
……

对于opencv，是否有简单的方法输出线上的每个点？

Answer 1

下面是使用Python/OpenCV/Numpy获取与图像中像素相交的直线坐标的一种方法。我使用np.argwhere获取图像中非零强度像素的坐标

进口cv2 将numpy作为np导入

y1=-304 #point1_y
y2=477 #point2_y
x1=-957 #point1_x
x2=883 #point2_x

# draw line in white on black background
img=np.zeros((300,300),np.uint8)
cv2.line(img,(x1,y1),(x2,y2),255,1)

# get coordinates
coords = np.argwhere(img)
print(coords)

cv2.imshow('img', img)
cv2.waitKey(0)
cv2.destroyAllWindows()

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Answer 2

我不知道使用opencv是否可行，但是使用numpy也是可行的（因为您在代码中使用numpy，我假设您可以这样做）

import numpy as np
x = [-957, 883]
y = [-304, 477]
x_coor = np.arange(1, x2)
y_coor = np.interp(x_coor, x, y)
coordinates = np.column_stack((x_coor, y_coor))