正则表达式提取包含三个元音的单词

Question

我正在尝试创建一个函数，从下面的字符串中提取具有3个连续元音的单词

import re
def three_vowel_words(text):
     pattern =  "[\w]+[aeiou]{3}"
     result = re.findall(pattern, text)
     return result

print(three_vowel_words("Our team was victorious over theirs in the contest."))
#the output should be ["victorious"]

print(three_vowel_words("Obviously, the acquaintance is serious and ambitious.")) 
#the output should be ["Obviously","acquaintance","serious","ambitious"]

然而，我得到的结果如下：

["victoriou"]

["Obviou", "acquai", "seriou", "ambitiou"]

有人能帮我纠正我的正则表达式模式，这样它就能提取完整的单词

多谢各位

Answer 1

使"\w+[aeiou]{3}\w+"这样单词的其余部分也匹配。在当前解决方案中，当找到3个连续元音时，匹配将停止

编辑：正如@usr2564301和@Tomerikoo所指出的，更一般的方法是"\w*[aeiou]{3}\w*"。这样，以3个元音开头或结尾或只有3个元音的单词也会匹配