我正在尝试使用SQL Alchemy进行查询,但我想从一个包含大约57列的表中“选择”20列,我知道这样做的方法是
session.query(Table.col1, Table.col2, Table.col3, Table.col4......).all()
但它是如此低效,而且肯定有更好的方法来实现这一点
我尝试过但没有成功,但离成功越来越近的是:
# "columns" is a dictionary that contains all the column names, it looks more or less like this (shorter version
columns = {"Account ID": "AR3",
"Account Origination Month": "AR55",
"Origination balance": "AR66",
"Product": "AR10",
"Repayment Type": "AR69",
"Original Loan Term (in months)": "AR61",
"Initial Product Term (in months)": "AR106",
"Initial rate/margin": "AR109",
"Initial Rate Type": "AR107",
"Reversion margin": "AR119",}
columns_sqla = ", ".join(["Table."+str(value) for key, value in columns.items()])
>>> columns_sqla
'BoE.AR3, BoE.AR55, BoE.AR66, BoE.AR10, BoE.AR69, BoE.AR61, BoE.AR106, BoE.AR109, BoE.AR107, BoE.AR119'
那么我会:
session.query(columns_sqla)
但它会抛出一个错误,因为它是一个字符串,并且无法识别它
您可以尝试如下所述的变量解包机制:
还可以运行下面的代码以获得更多的低调
相关问题 更多 >
编程相关推荐