Python程序，用于在给定的数字列表中查找最大序列

Question

我需要设计一个python程序，它输出给定数字列表中的最大序列

比如说,

INPUT = [1,2,3,2,4,5,6,7,8,1,0,4,5,6]

预期结果：

[4, 5, 6, 7, 8]

有人能帮我查一下密码吗

Answer 1

Sociopath's answer可以折叠成一个相对较短的内衬

$ python
Python 3.7.7 (default, May  7 2020, 21:25:33) 
[GCC 7.3.0] :: Anaconda, Inc. on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> from itertools import groupby as g
>>> d, e, l, λ, m = [1,2,3,2,4,5,6,7,8,1,0,4,5,6], enumerate, len, list, max
>>> [i[1]for i in m((λ(s)for k,s in g(e(d),lambda j:j[0]-j[1])),key=lambda j:l(j))]
[4, 5, 6, 7, 8]
>>> 

Answer 2

你能行

from itertools import groupby
from operator import itemgetter

new_l = []
for k, g in groupby(enumerate(data), lambda ix : ix[0] - ix[1]):
    new_l.append(list(map(itemgetter(1), g)))

print(max(new_l, key=lambda x: len(x)))

输出：

[4, 5, 6, 7, 8]

Answer 3

一种不使用内置python模块且代码复杂度为O（n）的方法

a = [1,2,3,2,4,5,6,7,8,1,0,4,5,6]

large_seq = []
large_seq_len = 0
temp_seq = []
temp_seq_len = 0
x = None

for i in a:
    if x is None or x + 1 == i:
        temp_seq.append(i)
        temp_seq_len += 1
    else:
        if temp_seq_len > large_seq_len:
            large_seq = temp_seq
            large_seq_len = temp_seq_len
        temp_seq = [i]
        temp_seq_len = 1
    x = i

if temp_seq_len > large_seq_len:
    large_seq = temp_seq

print(large_seq)

https://www.online-python.com/XNjaLm9vMS