Python获取pytorch张量大小

Question

我想知道如何在Python中得到这个张量的形状？我试过这个：

> len(x)

但这印的是1，为什么？我想在这里打印元组数，即3。使用len（x）仅打印1

有什么问题吗

这是张量：

 (x=array([[[[ 0.07499999,  0.        ],
         [ 0.0703125 ,  0.        ],
         [ 0.0703125 ,  0.        ],
         [ 0.09218752,  0.        ],
         [ 0.1953125 ,  0.        ],
         [ 0.05312502,  0.        ],
         [ 0.2890625 ,  0.        ],
         [ 0.015625  ,  0.        ],
         [ 0.32656252,  0.        ],
         [ 0.09218752,  0.        ],
         [ 0.23906249,  0.        ],
         [ 0.09218752,  0.        ],
         [ 0.22812498,  0.        ],
         [ 0.06406248,  0.        ],
         [ 0.19062501,  0.        ],
         [ 0.02031249,  0.        ],
         [ 0.17343748,  0.        ]],

        [[ 0.06875002,  0.        ],
         [ 0.06875002,  0.        ],
         [ 0.06875002,  0.        ],
         [ 0.09062499,  0.        ],
         [ 0.19375002,  0.        ],
         [ 0.05781251,  0.        ],
         [ 0.2921875 ,  0.        ],
         [ 0.01406252,  0.        ],
         [ 0.325     ,  0.        ],
         [ 0.08437502,  0.        ],
         [ 0.23124999,  0.        ],
         [ 0.09531248,  0.        ],
         [ 0.22031248,  0.        ],
         [ 0.06406248,  0.        ],
         [ 0.18906248,  0.        ],
         [ 0.02031249,  0.        ],
         [ 0.171875  ,  0.        ]],

        [[ 0.06718749,  0.        ],
         [ 0.06093752,  0.        ],
         [ 0.07187498,  0.        ],
         [ 0.078125  ,  0.        ],
         [ 0.18593752,  0.        ],
         [ 0.03437501,  0.        ],
         [ 0.2765625 ,  0.        ],
         [-0.00312501,  0.        ],
         [ 0.29843748,  0.        ],
         [ 0.078125  ,  0.        ],
         [ 0.21718752,  0.        ],
         [ 0.078125  ,  0.        ],
         [ 0.21249998,  0.        ],
         [ 0.07187498,  0.        ],
         [ 0.19062501,  0.        ],
         [ 0.13749999,  0.        ],
         [ 0.1796875 ,  0.        ]]]], dtype=float32), 0)

Answer 1

正如@rdas所指出的：

len is for the first-hand length of a sequence. It has no knowledge of potential sub-sequences

张量中有1list（这个列表有嵌套列表）。因此，张量的长度是1

Answer 2

看起来3个元组位于x的第一个（也是唯一的）索引中。在这种情况下，len(x[0])产生3