TypeError:“>=”在“dict”和“int”的实例之间不受支持

Question

正在使用我的代码获取以下错误

类型错误：'>；='“dict”和“int”实例之间不支持

知道为什么吗？尝试运行一个循环，查看每个学生的加权平均分数，然后给他们分配一个字母a-F。。。由于某种原因，循环在尝试拉取字母等级时拒绝工作

使用python 3.7.6

steve = {"Name": "Steve",
         "Homework": [90, 97, 75, 92],
         "Quizzes": [88, 40, 94],
         "Tests": [75, 90]}
alice = {"Name": "Alice",
         "Homework": [100, 92, 98, 100],
         "Quizzes": [88, 40, 94],
         "Tests": [75, 90]}
tyler = {"Name": "Tyler",
         "Homework": [0, 87, 75, 22],
         "Quizzes": [0, 75, 78],
         "Tests": [100, 100]}
print(steve)
print(alice)
print(tyler)


students = []
students = [steve, alice, tyler]

for i in students:
    print(f"Name: {i['Name']}\nHomework: {i['Homework']}\nQuizzes: {i['Quizzes']}\nTests: {i['Tests']}")


numbers = []
def average(numbers):
    return sum(numbers) / len(numbers)

def get_weighted_average(student):
        homework_average = average(student["Homework"])
        quiz_average = average(student["Quizzes"])
        test_average = average(student["Tests"])
        weighted_score = homework_average*.1 + quiz_average*.3 + test_average*.6
        return weighted_score

print(f"Steve's: {get_weighted_average(steve)}")
print(f"Tyler's: {get_weighted_average(tyler)}")
print(f"Alice's: {get_weighted_average(alice)}")

def get_letter_grade(score):
if score >= 90:
    return 'A'
elif score >= (80):
    return 'B'
elif score >= (70):
    return 'C'
elif score >= (60):
    return 'D'
else:
    return 'F'

print(get_letter_grade(50))
print(get_letter_grade(100))
print(get_letter_grade(72.5))

for i in students:
    print(f"Name: {i['Name']}'s weighted score is {get_weighted_average(i)}")
    print(f"Name: {i['Name']}'s letter grade is: {get_letter_grade(i)}")

Answer 1

此错误是由最后两行引起的，其中i是一个字典，并被用作get_letter_grade函数的参数，该函数应接受整数作为参数

你是说get_letter_grade(get_weighted_average(i))吗

将来，最好检查functinos中参数的数据类型，以便更容易查看错误发生的位置

Answer 2

在结尾处，您需要get_letter_grade(get_weighted_average(i))而不是get_letter_grade(i)