有时限/倒计时输入

Question

我对Python还很陌生，我想为我的学生编写一个（不是计算机）语言培训器。就像计时器在后台运行，学生必须快速输入单词来减慢/恢复倒计时-否则倒计时将达到零并显示一些“游戏结束”消息。（就像当一个特别探员不得不在计时器快到零的时候拆除炸弹一样。）

当然，有很多关于线程的解释听起来是正确的方法，但是到目前为止，我还没有发现任何一个计时器与（时间限制）raw_input结合在一起的东西。你们中有谁能给我一个我忽略的教程/讨论的指针吗？在

Answer 1

import threading
import time
import os

def ask():
    """
    Simple function where you ask him his name, if he answers
    you print message and exit
    """
    name = raw_input("Tell me your name, you have 5 seconds: ")
    exit_message = "Wohoho you did it..Your name is %s" % name
    exit(exit_message)

def exit(msg):
    """
    Exit function, prints something and then exits using OS
    Please note you cannot use sys.exit when threading..
    You need to use os._exit instead
    """
    print(msg)
    os._exit(1)

def close_if_time_pass(seconds):
    """
    Threading function, after N seconds print something and exit program
    """
    time.sleep(seconds)
    exit("Time passed, I still don't know your name..")

def main():
    # define close_if_time_pass as a threading function, 5 as an argument
    t = threading.Thread(target=close_if_time_pass,args=(5,))
    # start threading
    t.start()
    # ask him his name
    ask()

if __name__ == "__main__":
    main()

Answer 2

你不必通过线程来完成，你可以在一个线程中以特定的频率运行你的“逻辑”，每次迭代都通过时间增量方法重新计算倒计时。这是多少电子游戏生产。在

假设您以60hz的频率运行此伪代码方法：

delta = timenow-timelast;
countdown -= delta;
if(input)
    processInputHere;

您应该能够将伪代码转换为python代码以使其正常工作