如何打印格式为网格的二维列表？

Question

目前，我已经做了这个代码

def grid_maker(h,w):
    grid = [[["-"] for i in range(w)] for i in range(h)]
    grid[0][0] = ["o"]
    print grid

>>>grid_maker(3,5) => [[['o'], ['-'], ['-'], ['-'], ['-']], [['-'], ['-'], ['-'], ['-'], ['-']], [['-'], ['-'], ['-'], ['-'], ['-']]] 

我想制作另一个函数，该函数将接收生成的2d数组并以如下格式打印出来：

o----
-----
----- 

然而，我不确定从哪里开始

Answer 1

使用字符串连接（）

for row in grid:
    print ''.join(*zip(*row))

或作为一个班轮：

print '\n'.join(''.join(*zip(*row)) for row in grid)

但如果您愿意建议您将所有内容更改为：

def grid_maker(h,w):
    grid = [["-" for _ in range(w)] for _ in range(h)]
    grid[0][0] = "o"
    return grid

print '\n'.join(''.join(row) for row in grid_maker(5,5))

Answer 2

如果要使用grid_maker()的结果，必须使用return返回其结果：

def grid_maker(h, w):
    grid = [["-" for i in range(w)] for i in range(h)]
    grid[0][0] = "o"
    return grid

我修改了它，因为我不认为每个元素都必须位于另一个list内

要打印“网格”，您可以迭代每个行，然后迭代每个元素：

def print_grid(grid):
    for row in grid:
        for e in row:
            print e,
        print

输出：

print_grid(grid_maker(3, 5))

o - - - -
- - - - -
- - - - -

Answer 3

如果您想“漂亮地”打印网格，每个子列表都在自己的行上，您可以使用^{}：

>>> grid=[[['o'], ['-'], ['-'], ['-'], ['-']], [['-'], ['-'], ['-'], ['-'], ['-']], [['-'], ['-'], ['-'], ['-'], ['-']]]

>>> from pprint import pprint
>>> pprint(grid)

[[['o'], ['-'], ['-'], ['-'], ['-']],
 [['-'], ['-'], ['-'], ['-'], ['-']],
 [['-'], ['-'], ['-'], ['-'], ['-']]]

它仍然会像您定义的那样将每个元素显示为一个列表，如果您想将它们显示为字符串，您必须像m.wasowski建议的那样使用连接