如何使用python从JSON中查找连续的父键和类型？

Question

我有几个json，我需要找到每个关键的连续父母。下面是一个json示例

   {
  "status": 0,
  "body": {
    "activities": [
      {
        "date": "2018-12-12",
        "data": [
          {
            "cid": 1,
            "steps": 313
          },
          {
            "cid": 2,
            "steps": 345
          },
          {
            "cid": 3,
            "steps": 577
          }
        ]
      },
      {
        "date": "2018-12-14",
        "data": [
          {
            "cid": 1,
            "steps": 313
          },
          {
            "cid": 2,
            "steps": 345
          },
          {
            "cid": 3,
            "steps": 577
          }
        ]
      }
    ],
    "more": false,
    "offset": 200
  }
}

使用

keys_list = get_all_keys(my_json)
keys_list = list(dict.fromkeys(keys_list))

我可以获取json中的所有键，例如['status'、'body'、'activities'、'date'、'data'、'cid'、'steps'、'more'、'offset'] 但我也希望得到每个键的连续父母和类型如下

For activities key: {{body.activities[]}}
For data key: {{body.activities[].date}} 
For cid key: {{body.activities[].data[].cid}}
For steps key: {{body.activities[].data[].steps}}

[]符号表示其字典类型键

我使用一个函数

def find_path(dict_obj,key,i=None):
    for k,v in dict_obj.items():
        # add key to path
        path.append(k)
        if isinstance(v,dict):
            # continue searching
            find_path(v, key,i)
        if isinstance(v,list):
            # search through list of dictionaries
            for i,item in enumerate(v):
                # add the index of list that item dict is part of, to path
                path.append(i)
                if isinstance(item,dict):
                    # continue searching in item dict
                    find_path(item, key,i)
                # if reached here, the last added index was incorrect, so removed
                path.pop()
        if k == key:
            # add path to our result
            result.append(copy(path))
        # remove the key added in the first line
        if path != []:
            path.pop()

find_path(example2,"activities") #['body', 'activities']
find_path(example2,"cid") #['body', 'activities', 0, 'data', 0, 'cid']

寻找连续的父母。但我也需要钥匙的类型，例如

For cid key: {{body.activities[].data[].cid}}

或

['body', 'activities[]', 'data[]', 'cid']