我遇到一个比较奇怪的问题
我想解码python脚本参数,存储并分析它们。在以下命令中,-r选项用于确定要创建的报告类型
python脚本启动:
%run decodage_parametres_script.py -r junit,html
python脚本选项解析用于填充字典,结果是: 当前选项:
{'-cli-no-summary': False, '-cli-silent': False, '-r': ['junit', 'html']}
然后我想测试-r选项,下面是代码:
for i in current_options['-r']:
# for each reporter required with the -r option:
# - check that a file path has been configured (otherwise set default)
# - create the file and initialize fields
print("trace i", i)
print("trace current_options['-r'] = ", current_options['-r'])
print("trace current_options['-r'][0] = ", current_options['-r'][0])
if current_options['-r'][i] == 'junit':
# request for a xml report file
print("request xml export")
try:
xml_file_path = current_option['--reporter-junit-export']
print("xml file path = ", xml_file_path)
except:
# missing file configuration
print("xml option - missing file path information")
timestamp = get_timestamp()
xml_file_path = 'default_report' + '_' + timestamp + '.xml'
print("xml file path = ", xml_file_path)
if xml_file_path is not None:
touch(xml_file_path)
print("xml file path = ", xml_file_path)
else:
print('ERROR: Empty --reporter-junit-export path')
sys.exit(0)
else:
print("no xml file required")
我想尝试默认报告生成,但我甚至没有点击打印(“请求xml导出”)行,以下是控制台结果:
trace i junit
trace current_options['-r'] = ['junit', 'html']
trace current_options['-r'][0] = junit
我想这可能是一个类型问题,我尝试了以下测试:
In [557]: for i in current_options['-r']:
...: print(i, type(i))
...:
junit <class 'str'>
html <class 'str'>
In [558]: toto = 'junit'
In [559]: type(toto)
Out[559]: str
In [560]: toto
Out[560]: 'junit'
In [561]: toto == current_options['-r'][0]
Out[561]: True
所以我的行断言if current_options['-r'][i] == 'junit'
:应该以True结尾,但事实并非如此。
我是不是错过了一些琐碎的事情
有人能帮我吗
您正在按字符串数组进行迭代
在您的情况下
i
将是:junit
在第一次迭代中html
在下一次迭代中您的if条件(从解释器的角度来看)如下所示:
而不是预期的:
解决方案1:
您需要遍历
range(len(current_options['-r']))
解决方案2
更改比较器:
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