如何在re.sub（）中为正则表达式搜索设置停止条件

Question

我有一个文本块，我想从中删除短语

"Adaptation" means a work based upon the Work, or cAt upon the Work and other pre-existing works, such as a f translation, DOG adaptation, derivative work, arrangement of music or other alterations of a literary or artistic work, or phonogram f or performance and includes cinematographic adaptations or any

我想删除cAt和f之间DOG和f之间或rugrats和f之间的任何文本。为了方便起见，我突出显示了文本框中的术语

每个短语（cAt，DOG，rugrats，f）前后各有一个空格

这是我的密码

clean = `TEXT SHOWN ABOVE`
segment_start = [' cAt ', ' DOG ', ' rugrats ']
segment_end = ' f ' 

for start in enumerate(segment_start):
    clean = re.sub('{}.*{}{1}'.format(start, segment_end), ' ', clean)

我想退出

"Adaptation" means a work based upon the Work, or cAt upon the Work and other pre-existing works, such as a f translation, DOG adaptation, derivative work, arrangement of music or other alterations of a literary or artistic work, or phonogram f or performance and includes cinematographic adaptations or any

然后就这样结束了

"Adaptation" means a work based upon the Work, or translation, or performance and includes cinematographic adaptations or any

我的代码出错了。它找到段的开始，然后找到段的最后一次出现f，并删除其间的所有内容

它是这样做的

"Adaptation" means a work based upon the Work, or cAt upon the Work and other pre-existing works, such as a f translation, DOG adaptation, derivative work, arrangement of music or other alterations of a literary or artistic work, or phonogram f or performance and includes cinematographic adaptations or any

Answer 1

*是贪婪的重复：“0或更多，尽可能多”。这使得您的第一个匹配项可以抓取从cAt到最后一个f的所有内容，而不为DOG查询留下任何内容

改用*?：“0或更多，尽可能少”。这样，regexp将满足于只使用cAt和第一个f之间的位，并且DOGregex也将有它的一天