在python中如何在X秒后引发超时异常

Question

我有一个函数，我需要在X秒后引发异常我该怎么做？ 我尝试了这个代码，但它不起作用：

from eventlet.timeout import Timeout
timeout = Timeout(seconds, exception)
try:
   do somethins
finally:
   timeout.cancel()

Answer 1

根据the timeout documentation：

There are two Timeout caveats to be aware of:

• If the code block in the try/finally or with-block never cooperatively yields, the timeout cannot be raised. In Eventlet, this should rarely be a problem, but be aware that you cannot time out CPU-only operations with this class.
• If the code block catches and doesn't re-raise BaseException (for example, with except:), then it will catch the Timeout exception, and might not abort as intended.

如果在循环中没有执行任何IO/sleep，则不会发生超时。在