如何打印xpath匹配节点的代码？

Question

如何打印与xpath匹配对应的全文，也就是说，当前节点及其所有子节点，正如它在源xml中显示的那样

from lxml.html.soupparser import fromstring

strings = '<div><svg john=doe><path d="0"></path></svg></div>'
p = fromstring(strings)
for n in p.xpath('//path'):
    print(n)

# Desired results
<path d="0"></path>

Answer 1

您可以使用html.tostring(element_goes_here)方法，如下所示

from lxml import html
page = """<div><svg john=doe><path d="0"></path></svg></div>"""
tree = html.fromstring(page)
for n in tree.xpath('//path'):
    print(html.tostring(n))

屏幕截图：