t 转换从压缩对象到列表不包括任何特殊字符或引号:'convertion from zipped object to list doesn't

2024-04-18 16:56:19 发布

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尽管转换为列表,我还是得到了压缩对象

import itertools as it
def combi(i,j):
    string_maps = {"1": "abc","2": "def","3": "ghi","4": "jkl","5": "mno","6": "pqrs","7": "tuv","8": "wxy","9": "z"}
    string_maps=dict((int(k),v) for k,v in string_maps.items())
    list1=[]
    list1.append(string_maps.get(i))
    list2=[]
    list2.append(string_maps.get(j))
    list_new =list([zip(x,list2) for x in it.permutations(list1,len(list2))])
    print(list_new)

combi(4,3)

Tags: 对象in列表newforgetstringdef